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JulijaS [17]
4 years ago
15

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
dalvyx [7]4 years ago
4 0
2=1/6 2/12=1/6. 10/12=5/6
klasskru [66]4 years ago
3 0
The P(!2)=1-P(2)=1-1/6=5/6
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What is the volume of this cylinder? ​ 6m, 7m
FrozenT [24]

Answer:

198\:\mathrm{m^3}

Step-by-step explanation:

The volume of a cylinder is given by V=r^2\pi\cdot h, where r is the radius of the cylinder and h is the height.

What we're given:

  • r of 3
  • h of 7

Substituting given values, we get:

V=3^2\pi\cdot 7,\\V=9\cdot 3.14\cdot 7,\\V\approx 197.82\:\mathrm{m^3}=\boxed{198\:\mathrm{m^3}}, rounded the nearest cubic meter as requested in question.

6 0
3 years ago
Read 2 more answers
What is the vertex of the graph of the function f(x) = x² + 8x - 2?
chubhunter [2.5K]

Answer:

(4, -18)

Step-by-step explanation:

First  Use this formula for the x -axis  -b/2a  

-8/2(1) is -4

Then plug in -4 to the equation

(-4)^2+8(-4)-2 = -18

6 0
3 years ago
What is the solution to the equation 4/5x=3/10(x+4)?
Anastasy [175]

Answer:

\frac{12}{5}

Step-by-step explanation:

4/5x=3/10(x+4)  / · 10

8x=3(x+4)

8x=3x+12

8x-3x=12

5x=12  /:5

x=12/5

5 0
3 years ago
Answer to earn 10 points and brainliest<br><br> HSMath
sp2606 [1]

Answer:

Would it be 37?

Step-by-step explanation:

BODMAS shows that multiplication should be done first before addition so 21+16 equals 37. I’m not sure but this is my best guess

5 0
3 years ago
Read 2 more answers
Two ships leave a harbor at
natima [27]

Answer:

  30√3 ≈ 51.96 miles

Step-by-step explanation:

The distance between the two ships can be found using the Law of Cosines, or using your knowledge of the side relationships in special triangles.

__

Each ship is traveling at 10 mph, so after 3 hours will have traveled 30 miles.

The triangle OS1S2 formed by the harbor and the two ship locations is an isosceles triangle with base angles of 30°. Each half of OS1S2 is a 30-60-90 triangle whose longer leg is √3 times half the hypotenuse. The sum of those two "longer legs" is the distance between the ships.

The distance between ships is 2×15√3 = 30√3 ≈ 51.96 miles.

_____

<em>Additional comment</em>

If you prefer to use the Law of Cosines, you are looking for the length of the side opposite the 120° angle in a triangle with sides of 30 miles.

  c² = 30² +30² -2·30·30·cos(120°) = 30²(2-2·(-0.5)) = 3·30²

  c = 30√3 . . . . . take the square root (miles)

8 0
2 years ago
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