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lubasha [3.4K]
3 years ago
12

Use the quadratic form to solve 6x^2+3x+2=0.

Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer:

<em><u>Hello</u></em><em><u>!</u></em><em><u>!</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>its helpful to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Attachment below <br> algebra helppppp
yKpoI14uk [10]

Answer: second option.

Step-by-step explanation:

In order to solve this exercise, it is necessary to remember the following properties of logarithms:

1)\ ln(p)^m=m*ln(p)\\\\2)\ ln(e)=1

In this case you have the following inequality:

e^x>14

So you need to solve for the variable "x".

The steps to do it are below:

1. You need to apply ln to both sides of the inequality:

ln(e)^x>ln(14)

2. Now you must apply the properties shown before:

(x)ln(e)>ln(14)\\\\(x)(1)>2.63906\\\\x>2.63906

3. Then, rounding to the nearest ten-thousandth, you get:

x>2.6391

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2 years ago
Answer please!! urgent!!
Talja [164]

Answer:

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Step-by-step explanation:

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josh got 20% discount at a sale. He got a new shirt for $12. what was the original price of the shirt
jenyasd209 [6]

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Step-by-step explanation:

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Find the quotient of 675 and 5
Stells [14]
The quotient of 675 and 5 would be 135.
675/5=135
Hope this helps!
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3 years ago
A car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds. It maintains that speed for 5 seconds and then slows to a stop i
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Answer:

It is given that a car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds.

This means that in 5 seconds it's speed continuously increases to reach 46 mi/h from 23 mi/h.

It maintains that speed for 5 seconds and then slows to a stop in 5 seconds.

This means that the speed of the car is constant i.e. 46 mi/h i.e. the graph is a straight horizontal line parallel to the time axis.

And then it decreases to reach 0 mi/h.

5 0
2 years ago
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