The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
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Answer:
SORRY IF IM WRONG BUT I THINK ITS C
Step-by-step explanation:
PLEASE MARK BRAINLIEST REMOVE MY ANSWER IF WRONG!!!!!!!!
Answer:
9.99
Step-by-step explanation:
Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
<h3>How to Apply the Linear Pair Theorem?</h3>
Given the following angles in the image above:
Measure angle RSU = (17x - 3)°,
Measure angle UST = (6x – 1)°
To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:
m∠RSU + m∠UST = 180 degrees (linear pair]
Substitute the values
17x - 3 + 6x - 1 = 180
Solve for x
23x - 4 = 180
23x = 180 + 4
23x = 184
x = 8
m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]
m∠TSV = 180 - 2(6x - 1)
Plug in the value of x
m∠TSV = 180 - 2(6(8) - 1)
m∠TSV = 86°
Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
Learn more about the linear pair theorem on:
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What model? It only says please help me lol
