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2 years ago

Can anyone help me out on this

Mathematics

1 answer:

swat322 years ago

3 0

Answer: y = 1/8x+1

y=mx+b is slope intercept form

given m = 1/8 and a point we can find b by plugging in what we have

1=1/8(8)+b

1=1b

b=1

So then we know m = 1/8 and b = 1

y=1/8x+1 is the answer

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Triangle Q M N is shown. The length of Q M is 18, the length of M N is 17, and the length of Q N is 20. Law of cosines: a2 = b2

kvasek [131]

Answer:

53°

Step-by-step explanation:

17² = 18² + 20² - 2(18)(20) cos Q

289 = 324 + 400 - 720 cos Q

289 = 724 - 720 cos Q

-435 = -720 cos Q

0.6042 = cos Q

$cos^{-1} (0.6042) = Q$

Q = 52.83

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3 years ago

This is line segments

lianna [129]

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

Who is sacatoa joe in geometry

valkas [14]

I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such

anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent

(oposite side=side oposite the angle
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and of course the hypotonuse is the longest side aka, side oposite right angle)

3 0

3 years ago

What is the measure of А 50" 50° B C [Not drawn to scale] 50° 80 100 130

Paladinen [302]

Answer:

solution given :

<A=?

<B=50°

<C=50°

if it is a triangle:

<A+<B+<C=180°( sum of interior angle of a triangle is 180°)

<A=180-50-50

<A=80°

<A=80° is a required answer.

7 0

2 years ago

Help me please, I need help I don’t understand this problem

jarptica [38.1K]

The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.

Step-by-step explanation:

The equation for the maximum speed, s is given by s²= (16/9)x
where, x is the length of the water line in feet.

It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.

The question is asked to find the maximum speed when the length of the water is 30 feet.

Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.

Now, calculating the maximum speed :

s² = (16/9)(30)

s² = 480 / 9

s² = 53.3

Taking square root on both sides,

s = √53.3

s = 7.3

The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.

6 0

3 years ago