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2 years ago

PLEASE HELP !!!!!!! GEOMETRY

Mathematics

1 answer:

nata0808 [166]2 years ago

6 0

I came up with d and e as an answer

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20 points! Clear answers and good descriptions!<br> Thanks! :)

balu736 [363]

Answer:

1= b

2= f

Step-by-step explanation:

8 0

1 year ago

What is the inverse of f(x) = (5x+2)^2 for x > -2/5

Levart [38]

Answer:

it should be -2/5 or $\frac{\sqrt{x} }{5}$

Step-by-step explanation:

4 0

2 years ago

What does it mean when a researcher states that an observed effect or difference is significant with a confidence level of 99%?

icang [17]

Answer:

it affected more than half

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Last question of my homework pls <3

dimaraw [331]

Answer:

J(2, 5 )

Step-by-step explanation:

Using the section formula

$x_{J}$ = $\frac{1(-2)+2(4)}{2+1}$ = $\frac{-2+8}{3}$ = $\frac{6}{3}$ = 2

$y_{J}$ = $\frac{1(1)+2(7)}{2+1}$ = $\frac{1+14}{3}$ = $\frac{15}{3}$ = 5

Thus J = (2, 5 )

7 0

2 years ago

Match the following rational expressions to their rewritten forms.

Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

$1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}$

And the rewritten forms:

$(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}$

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

$(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}$

So, correct option is 3.

$(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}$

So, correct option is 1.

$(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}$

So, correct option is 2.

$(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}$

So, correct option is 4.

The answer is also attached in the answer area.

7 0

2 years ago