The inverted cone, hope it helps .
<u>Given:</u>
Mass of ice = mass of water = 5.50 kg = 5500 g
Temperature of ice = -20 C
Temperature of water = 75 C
<u>To determine:</u>
Mass of propane required
<u>Explanation:</u>
Heat required to change from ice to water under the specified conditions is:-
q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)
= m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)
= 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ
The enthalpy change for the combustion of propane is -2220 kJ/mol
Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane
Molar mass of propane = 44 g/mol
Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g
Ans: 75.15 grams of propane must be combusted.
Electrons are located in the orbits around the nucleus... we can name them as shells K,L,M,N...
Answer:
BaCl2-- Barium dichloride✔️, the dash (-) has the problem.
Fe2O3-- Iron(iii)oxide✔️, it's not Iron(ii)oxide.
CsNO2-- it's Cesium nitrogen dioxide✔️, not Cesium nitrate.
Mg(HCO3)2-- Magnesium hydrogen carbonate✔️, not magnesium(II) bicarbonate
