Explaining Radioactive Decay

Chemistry

2 answers:

DedPeter [7]3 years ago

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Answer:

Radioactive decay is the process in which the nucleus of an unstable isotope spontaneously changes, releasing particles and energy. An unstable isotope will continue to decay until it reaches the stable form of either a different isotope of the same element that is stable or a different element that is stable.

Explanation:

Ede4ka [16]3 years ago

3 0

Answer:

Sample Response: <em>Radioactive decay is the process in which the nucleus of an unstable isotope spontaneously changes, releasing particles and energy. An unstable isotope will continue to decay until it reaches the stable form of either a different isotope of the same element that is stable or a different element that is stable. </em>

<u>If you want to make your own make sure to include.</u>

- Radioactive decay is the process in which the nucleus of an unstable isotope spontaneously changes, releasing particles and energy.

- An unstable isotope will continue to decay until it reaches a stable form.

- The stable form could be a different isotope of the same element that is stable or a different element that is stable.

Explanation:

Edge 2021

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Ira Lisetskai [31]

Answer:

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Explanation:

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3 years ago

The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reactio

Nana76 [90]

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>

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