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Annette [7]
3 years ago
15

When the final velocity is less than the initial velocity, this is Question 4 options: speed time acceleration deceleration

Chemistry
1 answer:
zvonat [6]3 years ago
4 0

The correct choice is deceleration.

we know that

v = v₀ + at

v = final velocity  , v₀ = initial velocity , a = acceleration , t = time

In deceleration , net force acts in opposite direction of motion of the object. this net force produce acceleration is in opposite direction of motion of the object. hence the value of such acceleration is taken as positive if the velocities are in positive direction. this acceleration work to slow down the object instead of accelerating it. hence the final velocity of the object is smaller as compared to initial velocity.

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Balance the equations by inserting coefficients as needed.
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Answer:

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Explanation:

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4 years ago
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Determine the oxidation number (oxidation state) of each element in CH 4 . C : H : Determine the oxidation number (oxidation sta
AleksandrR [38]

Answer:

1. In CH₄ molecule:

The oxidation number of H = (+ 1)

The oxidation number of C = (- 4)

                   

2. In SO₂ molecule:

The oxidation number of O = (- 2)

the oxidation number of S = (+ 4)

3. In BF₃ molecule:

The oxidation number of F = (- 1)

the oxidation number of B = (+ 3)

                                                                                                     

Explanation:

Oxidation number represents the <em>oxidation state of an element</em> in a given chemical compound, <em>which can be zero, negative or positive. </em>

The overall charge on a given chemical molecule is equal to sum of the oxidation numbers of all the elements in that molecule.

Now, calculating the oxidation number-

1. In CH₄ molecule:

As we know,<u> the oxidation number of </u><u>H = (+ 1)</u>

and the overall charge on the molecule = 0

Let the oxidation number of C be x

∴ x + (+ 1) × 4 = 0

⇒ x = (- 4)

<u>Therefore, the oxidation number of </u><u>C = (- 4)</u>

                   

2. In SO₂ molecule:

As we know, <u>the oxidation number of </u><u>O = (- 2)</u>

and the overall charge on the molecule = 0

Let the oxidation number of S be x

∴ x + (- 2) × 2 = 0

⇒ x = (+ 4)

<u>Therefore, the oxidation number of </u><u>S = (+ 4)</u>

3. In BF₃ molecule:

As we know, <u>the oxidation number of </u><u>F = (- 1)</u>

and the overall charge on the molecule = 0

Let the oxidation number of B be x

∴ x + (- 1) × 3 = 0

⇒ x = (+ 3)

<u>Therefore, the oxidation number of </u><u>B = (+ 3)</u>

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4 years ago
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pantera1 [17]

Answer:

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