3 years ago

Assignment 01.12 learning path one activity

Mathematics

1 answer:

hodyreva [135]3 years ago

8 0

Why ask why? ';lkl!!!!!!!!!!

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Both are equal y. So you can set them equal to each other

9x+13=2x+48

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Westkost [7]

Answer:

$\dfrac{1}{2x(x-1)}$

Step-by-step explanation:

Given

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)$

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Consider the denominator:

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Hence, the fraction becomes

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Consider the expression in brackets:

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Divide:

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}$

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