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san4es73 [151]
3 years ago
14

Assignment 01.12 learning path one activity

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0
Why ask why?  ';lkl!!!!!!!!!!
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A rectangle has a length of x + 7 and a width of x-2. Which equation below describes the perimeter, P, of
valkas [14]

Answer:

            P = 4x  +  10

Step-by-step explanation:

perimeter of a rectangle = 2( width + length )

   P = 2 ( x - 2  +  x + 7 )

   P = 2 ( x + x  +  7 - 2 )

        P = 2 ( 2x +  5 )

            P = 4x  +  10

4 0
3 years ago
Solve each of the following systems using the linear combination method. Check your answers
Dvinal [7]
3x+5y=11 answer : 3x+5y-11=0

Step by step explanation:

3x+5y=11
Move the constant to the left

3x+5y-11=11-11
Eliminate the opposite

3x+5y=11

5y+8y
8 0
3 years ago
What is the likelihood the next crayon randomly selected will be yellow
tamaranim1 [39]
So.... there are 10 crayons and 8 are yellow.  

This means that 8/10 of the crayons are yellow.  

So the chance of picking a yellow one is 80%.  


To get this, you need to do 8/10 and make it over 100, which is 80/100.  Then, you turn this number into a percent by just dropping the 100 and adding a % to 80 (it's this easy if the bottom denominator is 100) 

The work should look something like this;

8:10
8/10
80/100
80%

So, there is an 80% chance that the crayon you pick will be yellow.  Any questions?
6 0
4 years ago
Find the slope of the line
Hoochie [10]

Answer:2/5

Step-by-step explanation:

Rise/Run

2/5

6 0
3 years ago
❗❗100POINTS❗❗+BRAINLIEST FOR CORRECT ANSWER<br>Show that 8x²-6x-275=0<br>thanks. ​
BaLLatris [955]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution ~

Area of a Trapezoid is :

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times (sum \: of \: parallel \: sides) \times height = 133 \: c {m}^{2}

so ~

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times ((x + 5) + (3x - 2)) \times (2x - 3) = 133 \:

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times (x + 5+ 3x - 2) \times (2x - 3) = 133 \:

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times (4x + 3) \times (2x - 3) = 133 \:

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}   \times(8 {x}^{2} - 12x + 6x - 9)   = 133 \:

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}   \times(8 {x}^{2} - 6x - 9)   = 133 \:

\qquad \sf  \dashrightarrow \:  (8 {x}^{2} - 6x - 9)   =( 133  \times 2)\:

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 9    =266\:

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 9     - 266 = 0

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 275 = 0

hence, we got the required equation ~

3 0
2 years ago
Read 2 more answers
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