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SIZIF [17.4K]
3 years ago
10

Solve each of the following systems using the linear combination method. Check your answers

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0
3x+5y=11 answer : 3x+5y-11=0

Step by step explanation:

3x+5y=11
Move the constant to the left

3x+5y-11=11-11
Eliminate the opposite

3x+5y=11

5y+8y
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Find the value of y so that WX is perpendicular to YZ
Alexxandr [17]

step 1

Find out the slope WX

W(2,-3) and X(-4,9)

m=(9+3)/(-4-2)

m=12/-6

m=-2

step 2

Find out the slope YZ

Y(5,y) and Z(-1,1)

m=(1-y)/(-1-5)

m=(1-y)/-6

m=(y-1)/6

step 3

Remember that

If two lines are perpendicular

then

their slopes are negative reciprocal

that means

(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2

solve for y

2y-2=6

2y=6+2

2y=8

<h2>y=4</h2>
8 0
1 year ago
How do you do this question?
Hitman42 [59]

The central angle corresponding to AOB is half of the 8pi/9 radians mentioned, meaning that the central angle of AOB is 4pi/9.

Converting that to degrees:

4pi/9 180 degrees

-------- * -------------------- = 80 degrees.

1 pi

4 0
3 years ago
Read 2 more answers
The radius of a circle is 3 millimeters. What is the circle's area? r=3 mm Use 3.14 for ​. square millimeters
Lena [83]
I’m pretty sure it’s 3,140,000
6 0
3 years ago
Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
4 years ago
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
maks197457 [2]
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.

So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
5 0
3 years ago
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