3x^2+2x+27 find g(p+4)

a grocer stacks apples in a pyramid-like stack whose rectangular base is 7 apples by 5 apples. each apple above the first level

g100num [7]

The arrangement of the apples in the stack is in a sequence that can be

used to find the number of apples in each row and in the stack.

Correct response:

The number of apples in the stack are <u>85 apples</u>

<h3>How to find the sum of a sequence</h3>

The given parameters are;

Dimensions of apples in the rectangular base = 7 apples by 5 apples

Number of apples on which each apple above rests = 4 apples

Required:

The number of apples in the stack.

Solution:

The dimensions, length and width of the apples in each row decreases

by 1 compared to the row on which the apple rests, as follows;

In the base, the dimension = 7 by 5

In the row directly above, the dimension = (7 - 1) by (5 - 1)

The number of apples sequence continues and is completed by a singles row of apples at the top, from which gives;

Number of apples in the stack = 7 × 5 + 6 × 4 + 5 × 3 + 4 × 2 + 3 × 1 = 85

The number of apples in the tack = <u>85 apples</u>

Learn more about sequence and series here:

brainly.com/question/13043887

4 0

2 years ago

If, for all x, f'(x)=(x-2)^4(x-1)^3, it follows that funtaion f has

Elenna [48]

Answer:

We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .

4 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

Aladdin had two envelopes to start. He bought three packs of

Stells [14]

Since it starts with 2 envelopes, subtract 2 from 17 to get how many and in all 3 packs.
17 - 2 = 15
Now, we divide that number by 3 to get how many are in each envelope.
15 / 3 = 5
There are 5 envelopes in each pack.

8 0

3 years ago

Y = 3 sin2x, y = 0, 0 ≤ x ≤ π; about the x−axis

Dominik [7]

I assume you're revolving the region with those bounds about the x-axis, and supposed to find the volume.

Via the disk method,

$\displaystyle\pi\int_0^\pi(3\sin2x)^2\,\mathrm dx=9\pi\int_0^\pi\sin^22x\,\mathrm dx$

Recall the half-angle identity for sine:

$\sin^2t=\dfrac{1-\cos2t}2$
$\implies\displaystyle\frac{9\pi}2\int_0^\pi(1-\cos4x)\,\mathrm dx$
$=\displaystyle\frac{9\pi}2\left(x-\frac14\sin4x\right)\bigg|_{x=0}^{x=\pi}$
$=\dfrac{9\pi^2}2$

8 0

3 years ago