Answer:
Step-by-step explanation:
10)
P10 = (2,7)
and parallel to y -4x = 5
y = 4x + 5
so any thing with a slope of 4 but going thur P1
y-7 = 4(x-2)
y-7 = 4x -8
10) y = 4x -1
11)
P11 = (5,-1)
and parallel to
y = -1/2x + 2
anything with a slope of -1/2 but going thur P2
y- (-1) = -1/2(x-5)
y + 1 = -1/2x +5
11) y = -1/2x + 4
12)
P12 = ( 3, 0 )
-2y + 3x = 0
perpendicular to, so the slope is reciprocal and opposite sign
3x = 2y
3/2x = y
y = 3/2x
-2/3 is the perpendicular slope
y-0 = -2/3(x-3)
12) y = -2/3x + 2
13)
P13= ( 6, 3)
3x- y = 6
perpendicular to, so the slope is reciprocal and opposite sign
3x-6 = y
y = 3x -6
-1/3
y-3 = -1/3(x-6)
y-3 = -1/3x + 2
13) y = -1/3x + 5
