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Natali5045456 [20]
3 years ago
10

25.5 g of methane burns in the combustion reaction below. How much water is produced in this reaction

Chemistry
1 answer:
gulaghasi [49]3 years ago
5 0
CH4 + O2 ===> H2O + CO2 Bare Equation. This is a Combustion Reaction.
CH4 + 2O2====>2H2O + CO2 Balanced equation. You start with this.

Step One
=======
Find the moles of Methane.
1 mole of methane has a mass of
C = 12
O2 = 2 * 16 = 32
1 mol of  CO2 = 12 + 32 = 44 grams / mole

Step Two 
======
Calculate the number of moles of methane.
given mass (g) = 25.5 grams
molar Mass = 44

mol = given mass / molar mass
mol = 25.5 / 44
mol = 0.5795 mols methane.

Step Three
========
Find the moles of water.
For ever mole of methane, 2 moles of water are produced.

1 mol methane. . . . . . .. .0.5795 mols methane
=========== . . . . .= .  .================ . . . . . 
2 mol water  . . . . . . . . . . .. .. . .x

Mole of water = 2 * 0.5795
mole of water = 1.159 

Step Four
=======
Find the mass of water.
1 mol = 2H + O = 2 + 16 = 18 grams / mol

desired mass = mols * Molar mass
desired mass = 1.159 * 18
desired mass = 20.86 grams of water.

If you do these questions by dimensional analysis, this problem can be done all in 1 step. It would look like this.

25.5 g [1mol /44grams]*[2mol water / 1 mol meth]*[18 grams / 1 mol water]


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A solid sample is hit with a hammer and breaks into jagged, irregular shards. What type of solid was it? A) molecular solid b) n
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8 0
2 years ago
How many moles of water are formed when 22 mol of methane combusts?
icang [17]
Methane is a hydrocarbon which when burns in air (combustion) produces carbon dioxide and water. The equation for the reaction;
CH4 +2O2 = CO2 +2H2O
When one mole of methane combusts 2 moles of water are formed
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7 0
3 years ago
How many moles are equal to 1.3 x 1024 atoms of aluminum?
marshall27 [118]

Answer:

<h3>The answer is 2.16 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.3 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 2.159468...

We have the final answer as

<h3>2.16 moles</h3>

Hope this helps you

8 0
3 years ago
(Brainliest) Please Help! Please do not give me a random, gibberish answer or I will report you and give you a low rating theref
nataly862011 [7]

Answer:

3.10g

Explanation:

Please see the attached picture for the full solution.

3 0
3 years ago
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