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3 years ago

25.5 g of methane burns in the combustion reaction below. How much water is produced in this reaction

1 answer:

5 0

CH4 + O2 ===> H2O + CO2 Bare Equation. This is a Combustion Reaction.
CH4 + 2O2====>2H2O + CO2 Balanced equation. You start with this.

Step One
=======
Find the moles of Methane.
1 mole of methane has a mass of
C = 12
O2 = 2 * 16 = 32
1 mol of CO2 = 12 + 32 = 44 grams / mole

Step Two
======
Calculate the number of moles of methane.
given mass (g) = 25.5 grams
molar Mass = 44

mol = given mass / molar mass
mol = 25.5 / 44
mol = 0.5795 mols methane.

Step Three
========
Find the moles of water.
For ever mole of methane, 2 moles of water are produced.

1 mol methane. . . . . . .. .0.5795 mols methane
=========== . . . . .= . .================ . . . . .
2 mol water . . . . . . . . . . .. .. . .x

Mole of water = 2 * 0.5795
mole of water = 1.159

Step Four
=======
Find the mass of water.
1 mol = 2H + O = 2 + 16 = 18 grams / mol

desired mass = mols * Molar mass
desired mass = 1.159 * 18
desired mass = 20.86 grams of water.

If you do these questions by dimensional analysis, this problem can be done all in 1 step. It would look like this.

25.5 g [1mol /44grams]*[2mol water / 1 mol meth]*[18 grams / 1 mol water]

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The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl

nevsk [136]

Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of caffeine extracted is $P = 39.8 \ mg$

Explanation:

From the question above we are told that

The K value is $K = 4.6$

The mass of the caffeine is $m = 40 mg$

The volume of water is $V = 2 mL$

The volume of caffeine is $v_c = 2 mL$

The number of times the extraction was done is n = 3

Generally the mass of caffeine that will be extracted is

$P = m * [\frac{V}{K * v_c + V} ]^3$

substituting values

$P = 40 * [\frac{2}{4.6 * 2 + 2} ]^3$

$P = 39.8 \ mg$

6 0

3 years ago

Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en

Bezzdna [24]

Answer:

10.19 g CO₂

4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following conversion factors:

1 gallon = 3.785 L

1 L = 1000 mL

Now we convert 1.24 gallons to mL:

1.24 gallon * $\frac{3.785L}{1gallon} *\frac{1000mL}{1L} =$ 4693.4 mL

We calculate the mass of Octane:

4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the stoichiometric ratios and molecular weights to calculate the mass of CO₂ and H₂O:

CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{8molCO_{2}}{1molOctane}$ * 44 g/mol = 10.19 g CO₂

H₂O ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{9molH_{2}O}{1molOctane}$ * 18 g/mol = 4.69 g H₂O

7 0

4 years ago

This family (ethane, propane, butane, etc) of materials is likely to have what set of properties?

Ilya [14]

This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.

The alkanes are non- polar solvents.
The alkanes are immiscible in water but freely miscible in other non-polar solvent .
The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.
The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.
The alkanes posses weak force of attraction that is weak van der waals force of attraction.

The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.

learn about butane

brainly.com/question/14818671

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7 0

2 years ago

In which of the following cases would sound reach each ear out of phase?

Galina-37 [17]

I hope this is the answer that you are looking for .