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2 years ago

Apply the VSEPR theory to find the bond angle between the atoms in carbon tetrafluoride (CF4).

2 answers:

7 0

To determine the structure of the molecule, we add the number of atoms that is bonded to the central atom. In this case, we have 4 fluorine atoms bonded to the central atom, carbon. We then look at the one pair of electrons and then choose the correct arrangement. For this case, the correct shape would be a tetrahedral. Therefore, the bond angle would be 109.5 degrees.

erastovalidia [21]2 years ago

6 0

Based on the valence shell electron repulsion theory, the bond angle between the atoms of Fluorine in carbon tetrafluoride is 109.5 degrees. CF4 having a sp3 hybridization would follow the tetrahedral shape which is the most stable conformation.

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Type the correct answer in the box. Express your answer to three significant figures.

VladimirAG [237]

Given:

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

To determine:

Theoretical yield of calcium phosphate, Ca3(PO4)2

Explanation:

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 = 96.1 g

Molar mass of Ca(NO3)2 = 164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

Therefore, # moles of Ca3(PO4)2 produced = 0.0589 * 1/3 = 0.0196 moles

Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g

7 0

2 years ago

Read 2 more answers

C como Se define una cuenca hidrogatica Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

sladkih [1.3K]

Answer:

Una cuenca es un área de tierra que drena todos los arroyos y la lluvia a una salida común, como la salida de un embalse, la boca de una bahía o cualquier punto a lo largo del canal de un arroyo.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0

2 years ago

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

Answer:

For a: The edge length of the unit cell is 314 pm

For b: The radius of the molybdenum atom is 135.9 pm

Explanation:

For a:

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$

Conversion factor used: $1cm=10^{10}pm$

Hence, the edge length of the unit cell is 314 pm

For b:

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

$R=\frac{\sqrt{3}a}{4}$

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

$R=\frac{\sqrt{3}\times 314}{4}=135.9pm$

Hence, the radius of the molybdenum atom is 135.9 pm

4 0

2 years ago

Which of the following is an example of a physical change?(1 point)

user100 [1]

Dissolving sugar in water

4 0

2 years ago

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I need help with science pls help me

ryzh [129]

Answer:

Explanation:

6. When insulating materials rub against each other, they may become electrically charged .

7. Charging by conduction involves the contact of a charged object to a neutral object.

8. Grounding is the process of removing the excess charge on an object by means of the transfer of electrons between it and another object of substantial size.

9. Grounding is the process of removing the excess charge on an object by means of the transfer of electrons between it and another object of substantial size.

6 0

2 years ago