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3 years ago

Apply the VSEPR theory to find the bond angle between the atoms in carbon tetrafluoride (CF4).

2 answers:

7 0

To determine the structure of the molecule, we add the number of atoms that is bonded to the central atom. In this case, we have 4 fluorine atoms bonded to the central atom, carbon. We then look at the one pair of electrons and then choose the correct arrangement. For this case, the correct shape would be a tetrahedral. Therefore, the bond angle would be 109.5 degrees.

erastovalidia [21]3 years ago

6 0

Based on the valence shell electron repulsion theory, the bond angle between the atoms of Fluorine in carbon tetrafluoride is 109.5 degrees. CF4 having a sp3 hybridization would follow the tetrahedral shape which is the most stable conformation.

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trapecia [35]

Answer:

Electrical conductivity

Explanation:

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3 years ago

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3 years ago

Read 2 more answers

The products in this reaction

Delvig [45]

Answer:

It’s either B or C:

В. have the same atom arrangement as the reactants.

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Explanation:

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3 years ago

What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm

lesya [120]

<u>Answer:</u> The mass of sucrose required is 69.08 g

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL (Density of water = 1 g/mL)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

$8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g$

Hence, the mass of sucrose required is 69.08 g

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3 years ago

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Snowcat [4.5K]

Answer:

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3 years ago