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vazorg [7]
3 years ago
10

Find the distance between the points given. (0, -6) and (9, 6)

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
AB=9
AC=`12
BC=x=?
ABC is a triangle with 90 degree
x2=(9)2+(12)2
x2=81+144
x2=225
x=15 so the distance between the points given is 15
nasty-shy [4]3 years ago
3 0
A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\The\ distance\ between\ A\ and\ B:\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\-------------------------\\(0;-6)\to x_1=0\ and\ y_1=-6\\(9;\ 6)\to x_2=9\ and\ y_2=6\\\\d=\sqrt{(9-0)^2+(6-(-6))^2}=\sqrt{9^2+12^2}=\sqrt{81+144}\\=\sqrt{225}=15\\\\Answer:\boxed{15}
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3 years ago
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Answer:

x = -1

Step-by-step explanation:

Solve for x:

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12 = 24 x + 12 + 24

Grouping like terms, 24 x + 12 + 24 = 24 x + (12 + 24):

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12 + 24 = 36:

12 = 24 x + 36

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24 x + 36 = 12

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36 - 36 = 0:

24 x = 12 - 36

12 - 36 = -24:

24 x = -24

Divide both sides of 24 x = -24 by 24:

(24 x)/24 = (-24)/24

24/24 = 1:

x = (-24)/24

The gcd of -24 and 24 is 24, so (-24)/24 = (24 (-1))/(24×1) = 24/24×-1 = -1:

Answer:  x = -1

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