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2 years ago

How do i do this? can someone help me please

1 answer:

8 0

Answer:

i dont know if this is right but the first one is 32.01

Step-by-step explanation:

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svlad2 [7]

The answer would be B.9

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3 years ago

vitfil [10]

41 hours of class I guess so

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3 years ago

Lera25 [3.4K]

Subtract 124 and 18

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3 years ago

melisa1 [442]

Answer:

$\frac{53}{6}$

Step-by-step explanation:

$\int\limits^4_3 {x^2-x} \, dx$

= [ $\frac{x^3}{3}$ - $\frac{x^2}{2}$ ] ← evaluate for upper limit - lower limit

= ( $\frac{64}{3}$ - $\frac{16}{2}$ ) - ( $\frac{27}{3}$ - $\frac{9}{2}$ )

= $\frac{64}{3}$ - 8 - 9 + $\frac{9}{2}$

= $\frac{155}{6}$ - 17

= $\frac{53}{6}$

5 0

3 years ago

Olenka [21]

Answer:

product

Step-by-step explanation:

hope it helps

5 0

3 years ago