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alekssr [168]
3 years ago
13

You and your friends decide to go to the movies. Each movie, m, costs $10. If each movie costs $10. What is the total cost for a

ll six people?
Mathematics
1 answer:
alexira [117]3 years ago
4 0

Answer:

6x10=60

Step-by-step explanation

each person is giving $10 to see a movie, you multiple it

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I need help with this problem.<br> x3+4x
Yuki888 [10]

Answer: x=0 x=2i x=-2i

if your factoring: x(x^2+4)

Step-by-step explanation:

(if your solving for x)

x^{3} +4x\\x(x^{2} +4)\\\\x=0\\\\x=\frac{-b}{2a}\frac{+}{-} \frac{\sqrt{b^2-4ac}}{2a} \\\\x=\frac{0}{2}\frac{+}{-} \frac{\sqrt{0^2-16}}{2} \\x={0}}\frac{+}{-} \frac{\sqrt{-16}}{2} \\

x={0}}\frac{+}{-} \frac{4i}{2} \\\\\\x=\frac{+}{-}2i

6 0
2 years ago
2a( 3a + b)- 3a(2a+4b)<br>​
Rom4ik [11]

Answer:

<em>-10ab</em>

STEP BY STEP EXPLANATION

<em>2</em><em>a</em><em> </em><em>(</em><em>3</em><em>a</em><em> </em><em>+</em><em> </em><em>b)</em><em> </em><em>-3a(</em><em>2</em><em>a</em><em> </em><em>+</em><em>4</em><em>b</em><em>)</em>

<em>6</em><em>a</em><em>²</em><em> </em><em>+</em><em> </em><em>2</em><em>a</em><em>b</em><em> </em><em>-</em><em> </em><em>6</em><em>a</em><em>²</em><em>-</em><em> </em><em>1</em><em>2</em><em>a</em><em>b</em>

<em>2</em><em>a</em><em>b</em><em>-</em><em>1</em><em>2</em><em>a</em><em>b</em><em> </em><em>6</em><em>a</em><em>²</em><em>-</em><em>6</em><em>a</em><em>²</em>

<em>-10ab</em>

Hope this will help you if not then sorry :)

8 0
3 years ago
Read 2 more answers
Determine whether x=5 is a solution to the compound inequality shown below. Justify your answer.
IrinaK [193]

Answer:

no

Step-by-step explanation:

x + 8 > 11 = x > 3

2x - 3 < 7 = x < 5

5 0
3 years ago
A research report claims that 20% of all individuals use Firefox to browse the web. A software company is trying to determine if
algol [13]

Answer:

Reject H0

Step-by-step explanation:

Z  = -2.474873734

 

survey (positive) 26

n (total) 200

p 0.2

 

p /point est. 0.13

POPULATION(min) 4000

np        >= 5 ? YES 40

n(1-p)  >= 5 ? YES 160

Sample is valid  

Confidence Level - "P" values  

99% 2.58

Confidence Interval - "P" values  

(0.0686 , 0.1914 )  

Reference=0.2 Reject H0

4 0
3 years ago
Crystal left her running shoes at school yesterday. Today she walked 44 miles to school to get her shoes, she ran home along the
Darina [25.2K]

Answer:

We can conclude that her walking speed is 2.1 miles per hour.

Step-by-step explanation:

We have the relation:

Speed = distance/time.

Here we know:

She walked for 44 miles.

And she ran along the same route, so she ran for 44 miles.

The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:

T + T' = 22 hours.

If we define: S = speed runing

                     S' = speed walking

Then we know that:

"and she ran 33 miles per hour faster than she walked."

Then:

S = S' + 33mi/h

Then we have four equations:

S'*T' = 44 mi

S*T = 44 mi

S = S' + 33mi/h

T + T' = 22 h

We want to find the value of S', the speed walking.

To solve this we should start by isolating one of the variables in one of the equations.

We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:

S'*T' = 44mi

(S' + 33mi/H)*T = 44mi

T + T' = 22h

Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:

T = 22h - T'

if we replace that in the other equations we get:

S'*T' = 44mi

(S' + 33mi/h)*(  22h - T') = 44 mi

Now we can isolate T' in the first equation to get:

T' = 44mi/S'

And replace that in the other equation so we get:

(S' + 33mi/h)*(  22h -44mi/S' ) = 44 mi

Now we can solve this for S'

22h*S' + (33mi/h)*22h + S'*(-44mi/S')  + 33mi/h*(-44mi/S') = 44mi

22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi

If we multiply both sides by S' we get:

22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'

We can simplify this to get:

22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0

22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0

This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:

S' = \frac{-628mi  \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)}  }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}

Then the two solutions are:

S' = (-628mi - 721mi)/44h = -30.66 mi/h

But this is a negative speed, so this has no real meaning, and we can discard this solution.

The other solution is:

S' = (-628mi + 721mi)/44h = 2.1 mi/h

We can conclude that her walking speed is 2.1 miles per hour.

7 0
3 years ago
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