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pychu [463]
2 years ago
6

UDD Question 6 10 pts Solve for x. Round to the nearest tenth (one decimal place). Just type the number, no unit of measurement.

G X 240 DI F 48 Next * Previous​

Mathematics
1 answer:
NISA [10]2 years ago
8 0

Answer:

The answer is;

54.4

Step-by-step explanation:

The given parameter are;

Triangle ΔFGH = Right triangle

The length of segment \overline {FH} = 48

The measure of ∠HFG = 28°

The measurement required = The measure of segment \overline {FG} = x

The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle

Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°

∠FGH = 62°

By sine rule, we have;

\overline {FH}/(sin ∠FGH) = \overline {FG}/(sin(∠FHG)

By substituting the known values, we have;

48/(sin 62°) = x/(sin(90°)

sin(90°) = 1, therefore, we have;

x/1 = x = 48/(sin 62°) = 54.4 (by rounding the answer to the nearest tenth)

x = 54.4

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3 years ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
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For graph f what is f(0)?
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Answer:

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Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

           Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= (2x-3)

We know, the diameter of circle is 2r

Diameter of Circle A is 2\times (2x-3)

Next as given sum of both circle diameter is 49 feet.

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distributing 2 with 2x and -3

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Cross multiplying both side.

⇒x=\frac{55}{5} = 11

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Next, subtituting the value of x to get the value of radius for Circle A.

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Circumference of Circle A= 2\times 3.14\times 19= 119.32

∴ Circumference of Circle A= 119.32

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