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Korolek [52]
3 years ago
9

*5 POINTS* plz help i need both of them

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

(a)

(f + g)(x) = f(x) + g(x)

f(x) + g(x) = 6x - 2 + 2x + 4 = 8x + 2

(b)

(f - g)(x) = f(x) - g(x)

f(x) - g(x) = 6x - 2 - (2x + 4) = 6x - 2 - 2x - 4 = 4x - 6

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Answer:

B

Step-by-step explanation:

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2 years ago
If a rectangle has a base of 6 units, and a height of 8 units, what is its area?
Morgarella [4.7K]

Answer:

a=48 units^2

Step-by-step explanation:

The area of a rectangle can be found using:

a=bh

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CAN SOMEONE PLEASE ANSWER THISS ASAP PLEASE
solong [7]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

                     =11.04-10.2/(5-1)

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the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.  

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2 years ago
How to find the inverse of g(x) = -3 +(3/5)x​
nasty-shy [4]

Answer:

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3 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

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2 years ago
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