Answer:
4400 Joules
73.33 Joules
25.9325 Joules
Explanation:
P = Power = 800 W
t = Time = 22 s
F = Force
r = Radius of arm = 90 cm
Energy

As the efficiency is 25%

Energy used in the race is 4400 Joules
Half of the energy is used in the arm

So, per stroke of paddle

The energy expenditure per arm stroke is 73.33 Joules
Displacement will be the half of the perimeter of the circle

Work done

The average force of the hand on the water is 25.9325 Joules
Answer:
a) 
b) 
Explanation:
Given:
height of water in one arm of the u-tube, 
a)
Gauge pressure at the water-mercury interface,:

we've the density of the water 


b)
Now the same pressure is balanced by the mercury column in the other arm of the tube:



<u>Now the difference in the column is :</u>



Answer:
Explanation:
You could try to say how helpful they are what they are and what they do
The orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
<h3>What is law of gravitation?</h3>
The law of gravitation states that the force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between the masses. Mathematically;
F = GMm/r²
where
M and m are the mass of ice cube and
Recall that;
s = Gm1/r^2
Also;
F = sm²
Substitute to have;
s = m²/F
For the centripetal acceleration
a = v²/r
Such that;
v²/r = Gm/r²
v² = Gm/r
v = √Gm/r
Substitute the given parameters into the formula to have:
V = √6.67×10^-11 * 5.68 x 10^26 / 3.00 x 10^5
V = 355358.97m/s = 3.56 * 10^6 m/s
Therefore the orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
Learn more on orbital speed here: brainly.com/question/7260440
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