-12 = 6.2*t - 4.9*t² → t = 2.32 sec (quadratic formula)
<span>V = Vi -g*t = 6.2 - 9.8*2.32 = -16.5 m/s</span>
Answer:
1. S-S Repulsion N-S Attraction
2. S-N Attraction N-N Repulsion
Explanation:
1. S-S Repulsion N-S Attraction
2. S-N Attraction N-N Repulsion
<h2>Answer: Ion
</h2>
An ion is an atom that is electrically charged by <u>gaining or losing one or more electrons.
</u>
To understand it better:
An atom has a nucleus with electrons around it and has a neutral charge. When an electron is added or detached, this atom is electrically charged, that is, it ceases to have a neutral charge and becomes an <u>ion</u>.
In this sense, there are two types of ions:
-Anions: ions negatively charged, by the gain of electrons in the atom.
-Cations: ions positively charged, by the loss of electrons in the atom.
Answer:
V1 =8.1 m/s
Explanation:
height at highest point (h2) = 4.1 m
height at lowest point (h1) = 0.8 m
acceleration due to gravity (g) = 9.8 m/s^{2}
from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore
mgh1 + 
= mgh2 + 
where
- speed at highest point = V2
- speed at lowest point = V1
- mass of the girl and swing = m
- at the highest point, the speed is minimum (V1 = 0)
- at the lowest point the speed is maximum (V2 is the maximum speed)
- therefore the equation becomes mgh1 + = mgh2
m(gh1 + 
) = m(gh2)
gh1 + = gh2
V1 = 
now we can substitute all required values into the equation above.
V1 = 
V1 = 
V1 =8.1 m/s
The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours
<h3>What is time?</h3>
Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)
To get the time that was saved on the 8.6-mile trip, we use the formula below.
Formula:
- Ts = (d/v₁)-(d/v₂)................. Equation 1.
Where:
- Ts = Time saved on the trip
- d = distance covered during the trip
- v₁ = Initial legal speed limit
- v₂ = final/current legal speed limit.
From the question,
Given:
- d = 86.0 mile
- v₁ = 55.0 mi/h
- v₂ = 75.0 mi/h
Substitute these values into equation 1
- Ts = (86/55)-(86/75)
- Ts = 1.564-1.147
- Ts = 0.42 h.
Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.
Learn more about time here: brainly.com/question/13893070
