The west constituent of their sequence needs to cancel out 58 mph crosswind. Subsequently a northwest direction is a 45-degree angle up to even with the destination. That is the third point out of the triangle and the right angle is at the destination. The top side is the west constituent of their flight the vertical side is their resultant travel and the hypotenuse is their definite distance flown. Since the 58 mph crosswind was negated by flying northwest, the distance from the beginning to the destination must be the same distance as the west component of their travel. The hypotenuse is square root of twice the side since it has 2 identical sides.
c = sqrt (58^2 + 58^2) = sqrt (6728) = 82.02
Alternative solution:
c = sqrt (2) * 58 = 1.414 * 58 = 82.02
Therefore, they have to fly 82.02 mph
Work done = force x distance
work done = 15 x 3
work done = 45J
Given :
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.
To Find :
The embankment in the height.
Solution :
Since no external force is acting in the system, therefore total energy will be conserved.
Initial kinetic energy of the object = Energy stored in spring
Also, initial potential energy is 0.
Now,
Therefore, the embankment height is 0.64 m.
Answer:
d. the coefficient of static friction is greater than the coefficient of kinetic friction.
Explanation:
The magnitude of the for required to be applied to the carton is given as equal to the frictional force of between the carton and the surface. So, when the carton is at rest:
F = μs*W
and when the carton is in motion:
F = μk*W
where,
F = Force Required
μs = coefficient of static friction
μk = coefficient of kinetic friction
W = Weight of Carton
Since, the weight is constant. Therefore, for the increase in the force required to move the carton at rest than the force required to keep pushing the carton in velocity, the coefficient of static friction must be greater than the coefficient of kinetic friction. Therefore, the correct option is:
<u>d. the coefficient of static friction is greater than the coefficient of kinetic friction.</u>
