Answer:
no
Explanation:
the metal spoon would be higher temperature
<span> static friction :) your very welcome
</span>
To solve this problem we will apply the Newtonian concept of gravitational acceleration produced by a planet. This relationship is given by:

Where,
G = Gravitational Universal Constant
M = Mass of Earth
r = Radius
The values given are based on the constants of the earth, so they can be expressed as


The relationship of gravity would then be given:

The relationship with the new planet, from the gravity of the earth would be given





The relationship with the weight of the earth would be given as:





Therefore the weigh on this planet would be 96N
Answer:
1. Newton's First Law of Motion
2.Newton's Third Law of Motion
3.Newton's Third Law of Motion
4.Newton's Second Law of Motion
5.Newton's Third Law of Motion
6.Newton's Second Law of Motion
7.Newton's First Law of Motion
Explanation:
Newton's First Law of Motion states that an object remain at rest or moving with a uniform velocity unless an external force acts on it. This is the law of inertia
Newton's Second Law of Motion states that the force of an objects is the product of mass and acceleration.
Newton's Third Law of Motion states that when two objects interact, a pair of forces act on the objects, and they are equal and act in opposite directions.
Answer:
a) x = 1.5 *10⁻⁴cos(524πt) m
b) v = -1.5 *10⁻⁴(524π)sin(524πt) m/s
a = -1.5 *10⁻⁴(524π)²cos(524πt) m/s²
c) x(1) = 1.5 *10⁻⁴ m = 1.5 *10⁻1 mm
x(0.001) = -1.13*10⁻⁵ m = -1.13*10⁻² mm
Explanation:
x = Acos(ωt)
ω = 2πf = 2π(262) = 524π rad/s
x = 1.5 *10⁻⁴cos(524πt)
v = y' = -Aωsin(ωt)
v = -1.5 *10⁻⁴(524π)sin(524πt)
a = v' = -Aω²cos(ωt)
a = -1.5 *10⁻⁴(524π)²cos(524πt)
not sure about the last part as time is generally not given in mm
I will show at 1 second and at 0.001 s to try to cover bases
x(1) = 1.5 *10⁻⁴cos(524π(1))
x(1) = 1.5 *10⁻⁴cos(524π)
x(1) = 1.5 *10⁻⁴(1)
x(1) = 1.5 *10⁻⁴ m = 1.5 *10⁻1 mm
x(0.001) = 1.5 *10⁻⁴cos(524π(0.001))
x(0.001) = 1.5 *10⁻⁴cos(0.524π)
x(0.001) = 1.5 *10⁻⁴(-0.0753268)
x(0.001) = -1.129902...*10⁻⁵ m
x(0.001) = -1.13*10⁻⁵ m = -1.13*10⁻² mm