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zhenek [66]
2 years ago
11

Whats the sum of 7/2/5 yards and 3/5 yards

Mathematics
1 answer:
soldi70 [24.7K]2 years ago
3 0
The sum is 8 wholes because if you add 3 and 2 you get 5 and the denominator stays the same so that becomes a whole and you add that 7 wholes plus the other 1 whole and you get 8
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Solve the inequality 2x>30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
If x^2 = 49, then x^-2 =
Natalija [7]

Answer:

0.001665973

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the variable in this expression?<br> 4b + 2b + 1⁄4
Shtirlitz [24]

Answer:

the variable is "b"

Step-by-step explanation:

7 0
2 years ago
According to Ohm’s law, which is stated as I = V ÷ R, which two sentences are true?
Sladkaya [172]

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2nd and 3rd

Step-by-step explanation:

4 0
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You are trying to estimate the average amount a family spends on food during a year. In the past the standard deviation of the a
timama [110]

Answer:

the number of families needed for the survey is 2,157

Step-by-step explanation:

The computation of the number of families needed for the survey is shown below:

Given that

The Standard deviation is $900

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z value at 99% = 2.58

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Based on the above information

The number of families needed for the survey is

n = (\frac{zs}{E})^2\\\\=  (\frac{2.58\times 900}{50})^2

= 2,157

Hence, the number of families needed for the survey is 2,157

8 0
3 years ago
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