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2 years ago

Can I name my Angle VTS as STV? And use it interchangeably in proving?

Mathematics

1 answer:

swat322 years ago

5 0

Answer:

both angles are the same, so you can use it interchangeably in proving.

But i suggest you to mantain only one, because it's easier to understand and it looks better.

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PLS HELP ME Giving brainliest!! On Monday, 316 students went on a trip to the zoo. All 6 buses were filled and 4 students had to

Sergeeva-Olga [200]

Answer:

xx = (316 - 4) ÷ 6

xx = 52 students per bus

4 0

2 years ago

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m

Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter: p = (51+37+20):2 = 54 m

Area of triangle:

$A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2$

Rate: ₹ 3 per m².

Cost: ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm

p = 11:2 = 5.5

$A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2$

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

$A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2$

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

$A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2$

8 0

2 years ago

Please help. Sooooo confused. GOAL is a quadrilateral in which GO is parallel to AL. If the measures of angle G=angle O = 40 deg

DanielleElmas [232]

Answer:

Angle A and L are 140 degrees each.

Step-by-step explanation:

Since GO and AL are parallel to each other, we can use the same side interior theorem to figure out angle A and L. Let's focus on GA first. We know that same side interior angles are supplementary (sum is 180 degrees). We know angle G is 40 degrees, so to figure out angle A, you do 180-40 which equals 140. So angle A is 140 degrees. You repeat this process for OL and you should also get 140 degrees for L.

3 0

2 years ago

The Smiths purchased 6 containers of ice cream for a party. Each container holds 9 cups of ice cream. Before the party, their so

morpeh [17]

Answer: they have 68 servings of ice cream left for the party

Step-by-step explanation:

The Smiths purchased 6 containers of ice cream for a party. Each container holds 9 cups of ice cream. This means that the total number of cups of ice cream that they have is

6 × 9 = 54 cups

Before the party, their sons ate 3 cups of ice cream altogether. This means that the number of cups of ice cream that they have left is

54 - 3 = 51 cups

One serving is 3/4 cup of ice cream. This means that the number of serving that they have left is

51/0.75 = 68

3 0

3 years ago

Hey can you please help me posted picture of question

Ira Lisetskai [31]

Answer:
40x² + 65x + 25

Explanation:
We will just multiply each term from the first bracket by each term from the second and then combine like terms to get the final expression.

This would be done as follows:
(5x + 5)(8x + 5)
5x(8x) + 5x(5) + 5(8x) + 5(5)
40x² + 25x + 40x + 25
40x² + 65x + 25

Hope this helps :)

6 0

3 years ago