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Afina-wow [57]
3 years ago
13

Sam reads 30 pages of a book in 40 minutes. Which statement identifies a person with the same reading rate as Sam?

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

Choice 3

Step-by-step explanation:

The reading rate of Sam is 0.75 pages/minute.

i.e 30 pages/40 minutes

The reading rate of Bill is 0.5 pages/minute

The reading rate of Francine is 0.72 pages/minute

The reading rate of Leroy is 0.75 pages/minute which is the same as Sam's.

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Solve for www. Give an exact answer in simplified form. 53w+13 < 56w + 16
ki77a [65]

The solution will be:  w>-1

<em><u>Explanation</u></em>

The given inequality is:   53w+13 < 56w + 16

First we will subtract 56w from both sides. So.....

53w+13-56w

Now we will subtract 13 from both sides. So.....

-3w

Then we need to divide both sides by -3. As here we are <u>dividing the inequality by a negative number, so we need to switch the inequality symbol</u>. So, we will get.......

\frac{-3w}{-3}>\frac{3}{-3}\\ \\ w>-1

Thus, the solution will be:  w>-1

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3 years ago
Radio signals travel at a rate of 3 x 10^8 meters per second. How many seconds would it take for a radio signal to travel from a
wel
Time = Distance / Speed   [ Already mentioned ]

Then, substitute the known values, 

t = (9.6 × 10⁶) / (3 × 10⁸)

t = 3.2 × 10⁻² s

In short, Your Answer would be Option B

Hope this helps!
4 0
3 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

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3 years ago
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KengaRu [80]


The least common multiple is 63.

Explanation: 63 is the least number that 3 7 and 9 can go into evenly. Therefore, it is the least common multiple.

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