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Vladimir79 [104]

3 years ago

15

Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.

2 answers:

Anton [14]3 years ago

5 0

Answer: 15.0

explanation: i dont know im just good at maths

4vir4ik [10]3 years ago

4 0

Answer:

15.0

Step-by-step explanation:

Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.

The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)

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Answer:

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Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.

Digiron [165]

Answer:

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Step-by-step explanation:

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Now the expression is as follows:

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Now we use the study of signs to solve this inequality.

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Observe the attached image.

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and

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3 years ago

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konstantin123 [22]

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Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.

sergiy2304 [10]

Answer:

76

2 real solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

Positive - 2 solutions
Equal to 0 - 1 solution
Negative - No solutions/Imaginary

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
[Discriminant] Evaluate exponents: 36 - 4(1)(-10)
[Discriminant] Multiply: 36 + 40
[Discriminant] Add: 76

This tells us that our quadratic has 2 real solutions.

8 0

2 years ago