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3 years ago

When does a soft page break occur in a document

1 answer:

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A soft page break is a place in a document or text that automatically separates pages. Soft page breaks are inserted automatically by word processing programs such as Microsoft Word, as opposed to hard page breaks that are inserted manually by the user to separate pages.

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The _____ class can be used to get user input using dialog boxes.

Ber [7]

Answer:

JOptionPane

Explanation:

The class "JOptionPane" are used to pop / create dialogue boxes for the user to enter the input for a question.
JOptionPane contains methods to create input dialogue boxes, message dialogue boxes, option dialogue boxes and confirm dialogue boxes.
The dialogue boxes can be just message dialogue boxes which gives some message to the user. It doesn't require anything to be input from the user. It is just a message box.
Where as input dialogue box requires the user to input something.
Confirm dialogue box asks the user to answer a question yes / no / cancel.
Option dialogue box asks the user to select the options.
So, option (d) JOptionPane is the answer for the question.
Option (a), (b) and (c) are used for different purposes but not to create dialogue boxes. So, options (a), (b) and (c) are not the correct answers for the question.

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3 years ago

Which technique is best suited to create technical drawings?

Tema [17]

Answer:

Mechanical pencils.

Clutch pencils.

Technical pens.

Rulers.

Compass.

Drawing boards.

Erasers.

Sharpeners.

Explanation:

'What makes a great Technical Drawing? ' Technically correct, accurate, complete, consistent and unambiguous. Check the brief (a lot – and at all stages of the drawing process).

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3 years ago

Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,

nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
P5 will not be allocated to any of the available space because none can contain it.
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

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3 years ago

Technical colleges offer certification in audio engineering through programs that are normally from 2 to 6 months long.

Murrr4er [49]

Answer:

False

Explanation:

i said so

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3 years ago

3. By default, Blender® remembers your last 32 actions and allows you to undo them one at a time by pressing CTRL+Z. (1 point)

Setler [38]

Answers:

(3) True
(4) Num Lock

Explanations:
(3) To undo any task in most of the softwares including Blender, CTRL + Z is used. If you want to double check, go to preference -> Input -> Search for undo. You would see CTRL + Z shortcut there for one time undo (as shown in the picture 1 attached.) Hence (TRUE).

(4) As in blender, during the scene creation, the designers usually use top, left, right or bottom view. Blender has the built-in keys set for those views. As you can see in the second image that the Top view is set to NumPad 7 (likewise others set to other numbers). In order to use the those numpad numbers, you must turn on the NumLock! Hence NumLock is the answer.

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3 years ago