Answer:
-3y
Step-by-step explanation:
-15(y2)4 ÷5y3y4
Rewrite the division as a fraction
<u>-15(y2)4</u>
5y3y4
Multiply y3 by y4 by adding the exponents
<u>-5(y2)4</u>
5y7
Cancel the common factor of -15 and 5
<u>-3(y2)4</u>
y7
Multiply the exponents in (y2)4
<u>-3y8</u>
y7
Cancel the common factor of y8 and y7
Factor y7 out of -3y8
<u>y7(-3y)</u>
y7
Multiply by 1
<u>y7(-3y)</u>
y7 × 1
Cancel the common factor which is y7 and y7
Rewrite the expression
<u>-3y</u>
1
Divide -3y by 1
-3y
The answer would be c i think but i could be wrong i was never good at box and whisker plots
Answer:
<h2>3Q + 2p</h2>
Step-by-step explanation:
![Q+p+Q+p+Q\\\\\text{combine like terms}\\\\=(Q+Q+Q)+(p+p)=3Q+2p](https://tex.z-dn.net/?f=Q%2Bp%2BQ%2Bp%2BQ%5C%5C%5C%5C%5Ctext%7Bcombine%20like%20terms%7D%5C%5C%5C%5C%3D%28Q%2BQ%2BQ%29%2B%28p%2Bp%29%3D3Q%2B2p)
Answer: 66.5
<u>Step-by-step explanation:</u>
Let θ represent ∠MLK
![\text{Then }cos\ \theta =\dfrac{9}{15}\quad \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{9}{15}\bigg)\quad \rightarrow \quad \theta = 53^o](https://tex.z-dn.net/?f=%5Ctext%7BThen%20%7Dcos%5C%20%5Ctheta%20%3D%5Cdfrac%7B9%7D%7B15%7D%5Cquad%20%5Crightarrow%20%5Cquad%20%5Ctheta%20%3D%20cos%5E%7B-1%7D%5Cbigg%28%5Cdfrac%7B9%7D%7B15%7D%5Cbigg%29%5Cquad%20%5Crightarrow%20%5Cquad%20%5Ctheta%20%3D%2053%5Eo)
Arc length (s) = radius (r) · θ (theta must be in radians)
![\stackrel\frown{JM}\ =\ \stackrel\frown{KM}\text{ so }\stackrel\frown{JK}\ =\ 2\stackrel\frown{KM}\\\\.\qquad \rightarrow \quad \stackrel\frown{JK}\ =\ 2\bigg(15\cdot 53^o\cdot \dfrac{\pi}{180}\bigg)\\\\.\qquad \rightarrow \quad \stackrel\frown{JK}\ =\ 2\bigg(\dfrac{53\pi}{12}\bigg)\\\\\.\qquad \rightarrow \quad \stackrel\frown{JK}\ =\ \dfrac{53\pi}{6}](https://tex.z-dn.net/?f=%5Cstackrel%5Cfrown%7BJM%7D%5C%20%3D%5C%20%5Cstackrel%5Cfrown%7BKM%7D%5Ctext%7B%20so%20%7D%5Cstackrel%5Cfrown%7BJK%7D%5C%20%3D%5C%202%5Cstackrel%5Cfrown%7BKM%7D%5C%5C%5C%5C.%5Cqquad%20%5Crightarrow%20%5Cquad%20%5Cstackrel%5Cfrown%7BJK%7D%5C%20%3D%5C%202%5Cbigg%2815%5Ccdot%2053%5Eo%5Ccdot%20%5Cdfrac%7B%5Cpi%7D%7B180%7D%5Cbigg%29%5C%5C%5C%5C.%5Cqquad%20%5Crightarrow%20%5Cquad%20%5Cstackrel%5Cfrown%7BJK%7D%5C%20%3D%5C%202%5Cbigg%28%5Cdfrac%7B53%5Cpi%7D%7B12%7D%5Cbigg%29%5C%5C%5C%5C%5C.%5Cqquad%20%5Crightarrow%20%5Cquad%20%5Cstackrel%5Cfrown%7BJK%7D%5C%20%3D%5C%20%5Cdfrac%7B53%5Cpi%7D%7B6%7D)
![\stackrel\frown{JK}+ \stackrel\frown{JPK}=\text{Circumference of the circle}\\\\\dfrac{53\pi}{6}+\stackrel\frown{JPK}=2\pi\cdot 15\\\\.\qquad \stackrel\frown{JPK}=30\pi-\dfrac{53\pi}{6}\\\\\\.\qquad \stackrel\frown{JPK}=\dfrac{180\pi}{6}-\dfrac{53\pi}{6}\\\\\\.\qquad \stackrel\frown{JPK}=\dfrac{127\pi}{6}\\\\\\.\qquad \stackrel\frown{JPK}=66.5](https://tex.z-dn.net/?f=%5Cstackrel%5Cfrown%7BJK%7D%2B%20%5Cstackrel%5Cfrown%7BJPK%7D%3D%5Ctext%7BCircumference%20of%20the%20circle%7D%5C%5C%5C%5C%5Cdfrac%7B53%5Cpi%7D%7B6%7D%2B%5Cstackrel%5Cfrown%7BJPK%7D%3D2%5Cpi%5Ccdot%2015%5C%5C%5C%5C.%5Cqquad%20%5Cstackrel%5Cfrown%7BJPK%7D%3D30%5Cpi-%5Cdfrac%7B53%5Cpi%7D%7B6%7D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cstackrel%5Cfrown%7BJPK%7D%3D%5Cdfrac%7B180%5Cpi%7D%7B6%7D-%5Cdfrac%7B53%5Cpi%7D%7B6%7D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cstackrel%5Cfrown%7BJPK%7D%3D%5Cdfrac%7B127%5Cpi%7D%7B6%7D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cstackrel%5Cfrown%7BJPK%7D%3D66.5)
Option B is correct
Why
3x=21
3(7) =21
21=21
Step-by-step explanation: