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KengaRu [80]
2 years ago
12

(5+3√2)² simplify the following​

Mathematics
2 answers:
Elden [556K]2 years ago
5 0

Hello!

Here, we apply the algebraic identity :

\boxed {(a + b)^{2} = a^{2} + 2ab + b^{2}}

Let's solve!

⇒ (5 + 3√2)²

⇒ (5)² + 2(5)(3√2) + (3√2)²

⇒ 25 + 30√2 + 18

⇒ \boxed {43 + 30\sqrt{2}}

∴ The final answer will be 43 + 30√2.

madam [21]2 years ago
3 0

Answer:

(5+3\sqrt{2} )^{2} =43+30\sqrt{2}  

≈85.43

Step-by-step explanation:

apply the binomial theorem to the square

=(5)^{2} +2(5)(3\sqrt{2} )+(3\sqrt{2} )^{2}

=25+30\sqrt{2} +18\\

=43+30\sqrt{2}

≈85.43

Hope this helps

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Step-by-step explanation:

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5 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

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A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

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