All categories

3 years ago

Anybody wanna help me with this one and 3 more I’ll cash app?

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

Answer:

x=14

Step-by-step explanation:

8x-4+6x-12=180

14x-16= 180

14x= 196

x= 14

You might be interested in

Help me plzzzz!!!!!

dolphi86 [110]

Store A is cheaper than B
The way to solve is pretty simple for B.
You have to divide the cost by the number of tubes.
So in this case:
9/3=3
15/5=3
21/7=3
See the pattern?
So the cost per lip gloss is $3.
Now for Store A:
Just divide 5.50/2
The answer is 2.75
Compare both numbers

2.75<3.00
So, store A is cheaper.

5 0

3 years ago

The mean absolute deviation is a measure of . This value represents the average distance each value is from the .

Oksanka [162]

Answer:

Step-by-step explanation:

Yes

7 0

3 years ago

Among all right triangles whose hypotenuse has a length of 12 cm, what is the largest possible perimeter?

Veronika [31]

Answer:

Largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

Step-by-step explanation:

We are given the following information in the question:

Right triangles whose hypotenuse has a length of 12 cm.

Let x and y be the other two sides of the triangle.

Then, by Pythagoras theorem:

$x^2 + y^2 = (12)^2 = 144\\y^2 = 144-x^2\\y = \sqrt{144-x^2}$

Perimeter of Triangle = Side 1 + Side 2 + Hypotenuse.

$P(x) = x + \sqrt{144-x^2} + 12$

where P(x) is a function of the perimeter of the triangle.

First, we differentiate P(x) with respect to x, to get,

$\frac{d(P(x))}{dx} = \frac{d(x + \sqrt{144-x^2} + 12)}{dx} = 1-\displaystyle\frac{x}{\sqrt{144-x^2}}$

Equating the first derivative to zero, we get,

$\frac{dP(x))}{dx} = 0\\\\1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0$

Solving, we get,

$1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0\\\\x = \sqrt{144-x^2}}\\\\x^2 = 144-x^2\\\\x = \sqrt{72} = 6\sqrt{2}$

Again differentiation P(x), with respect to x, using the quotient rule of differentiation.

$\frac{d^2(P(x))}{dx^2} = \displaystyle\frac{-(144-x^2)^{\frac{3}{2}}-x^2}{(144-x)^{\frac{3}{2}}}$

At x = $6\sqrt{2}$ ,

$\frac{d^2(V(x))}{dx^2} < 0$

Then, by double derivative test, the maxima occurs at x = $6\sqrt{2}$

Thus, maxima occurs at x = $6\sqrt{2}$ for P(x).

Thus, largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

7 0

3 years ago

How to do this question plz answer me step by step plzz plz

Firdavs [7]

Answer:

24.99 cm

Step-by-step explanation:

We are provided with the radius of the circle so we can use that to solve for the circumference(perimeter) of the circle. The formula to solve for the circumference is 2*pi*r.

2*pi*7 = 14pi = 43.98 cm

Although this is the circumference of the entire circle... To solve for the circumference of a quarter-circle we must find the quarter of that:

43.98 * 1/4 = 10.99 cm

We are already provided with the other two sides, which are both equal to 7 cm since they are radii.

Perimeter = 10.99 +7 + 7 = 24.99 cm

Hope this helps!

8 0

3 years ago

Find the length of side x in simplest radical form with a rational denominator.60°130°X

iren [92.7K]

We will solve using the law of sines as follows:

$\frac{1}{\sin(30)}=\frac{X}{\sin (60)}$

Now, we solve for X:

$\Rightarrow X=\frac{\sin(60)}{\sin(30)}\Rightarrow X=\sqrt[]{3}$

So, the length of X is sqrt(3).

5 0

1 year ago