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den301095 [7]
3 years ago
7

What's the increase from 8.00to 9.50

Mathematics
2 answers:
LekaFEV [45]3 years ago
5 0
9.50-8.00=1.50        check it: <span>1.50+8.00=9.50</span>
Vika [28.1K]3 years ago
4 0
9.50-8.00=1.50




check it:
1.50+8.00=9.50
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During a recent rainstorm, 8 centimeters of rain fell in Dubaku's hometown, and 2.36 centimeters of rain fell in Elliot's hometo
Nostrana [21]

Answer:

5.64 cm

Step-by-step explanation:

Required:How much more rain fell in Dubaku's town than in Elliot's town?

8 centimeters of rain fell in Dubaku's hometown

2.36 centimeters of rain fell in Elliot's hometown

We are asked to find how much more rain fell in Dubaku's town than in Elliot's town so it is calculated as the difference between the rain in both of there towns and is given by:

Difference in rain= 8-2.36

Difference in rain= 5.64 cm.

Therefore, 5.64 cm of more rain fell in Dubaku's town than in Elliot's town.

7 0
3 years ago
I just started learning about rate and I am stuck on a question.(A watch keeps perfect time but only has an hour hand. If the ho
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Answer:

36 minutes past 1, or 1:36

Step-by-step explanation:

A watch normally has an hour hand that does one revolution in 12 hours.

It takes 1 hour to go from the 1 o'clock position to the 2 o'clock position.

Since 1 hour equals 60 minutes, it takes 60 minutes to go from the 1 o'clock position to the 2 o'clock position.

The hour hand is 3/5 of the way from 1 to 2, so the number of minutes past 1 o'clock is 3/5 of 60 minutes.

3/5 of 60 minutes =

= 3/5 * 60 minutes

= 3/5 * 60/1 minutes

= 180/5 minutes

= 36 minutes

The time is 36 minutes past 1, or 1:36

7 0
3 years ago
2. (x3 – 6x2) (x – 7)
ira [324]

Answer:

I believe this is the answer you are looking for:

x3-6x2-7x

Step-by-step explanation:

5 0
3 years ago
The length of each side of a square is 6 feet more than the length of a side of a regular Octagon. The perimeter of the square i
goldfiish [28.3K]

9514 1404 393

Answer:

  • square: 12 ft sides
  • octagon: 6 ft sides

Step-by-step explanation:

This problem can be worked in your head.

If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.

__

We can let s represent the side length of the octagon. Then we have ...

  8s = perimeter of octagon

  4(s +6) = perimeter of square

These are equal, so ...

  4(s +6) = 8s

  s +6 = 2s . . . . . . divide by 4

  6 = s . . . . . . . . . . subtract s

The octagon has 6-ft sides; the square has 12-ft sides.

8 0
3 years ago
How to find the inverse of a function
Studentka2010 [4]
Switch the x and the y and solve for y 
eg inverse of 2y= 3x+1
swith x and y
2x=3y+1
now solve for y
y =(2x-1)/3
5 0
4 years ago
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