3 years ago

Here:Hdhdgdhdvdvvdgdjdbd

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

because

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AleksAgata [21]

Answer:

Step-by-step explanation:

sorry if wrong good luck

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B5%7D%20%29%20%7B%7D%5E%7Bx%7D%20%3D%20125" id="TexFormula1" title="( \f

anzhelika [568]

Well we know that... $a^{-1}=\frac{1}{a^{1} }\\$ .

So... $(\frac{1}{5})^{-1}=\frac{1}{\frac{1}{5}^{1}}=5\\\\$ .

Because $5^{3}=125$ ,

$\frac{1}{5}^{-1*3}=125\\ x=-1*3=-3$

answer: -3

8 0

3 years ago

Please help solve this equation. Show all steps please. No links or files.

maksim [4K]

Answer:

See below

Step-by-step explanation:

c = (a^2 + 3b) / 4 multiply both sides by 4

4c = a^2 + 3b subtract a^2 from both sides

4c - a^2 = 3b now divide both sides by 3

(4c-a^2) / 3 = b

3 0

2 years ago

What is the domain and range of the relation [(1, -8), (-7,8), (-3, 7). (-3, -5]?

Nadusha1986 [10]

Step-by-step explanation:

domain = {-7, -3, 1}

range ={-8, -5, 7, 8}

6 0

3 years ago

The third term is given 2 and the sixth term is 15 . find the first term and the common ratio .

Mumz [18]

Answer:

Answer to your query is provided below in the image attached

8 0

3 years ago

Here:Hdhdgdhdvdvvdgdjdbd​

Here:Hdhdgdhdvdvvdgdjdbd