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3 years ago

If you reflect point A (3, 4) over the y-axis, what is the reflected point?

Mathematics

1 answer:

zavuch27 [327]3 years ago

6 0

The rule for reflecting a point over the y-axis is this:

(x, y) ---> (-x, y)

The x term becomes the opposite and the y term stays the same

(3, 4) ---> (-3, 4)

Hope this helped! Let me know if you have any further questions!

~Just a girl in love with Shawn Mendes

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What is an equation of the line that is parallel to y=9-5x and passes though (0,8)?

Murljashka [212]

y = 8-5x

Step-by-step explanation:

When two lines are parallel, it means their gradients are the same.

from the given equation

y = 9-5x

and comparing with the general equation of a line

y = mx+c, where m is the gradient, and c is the <em>y-intercept, </em>

m = -5

you can form a line parallel to that using the points (0,8)

(y-8)/(x-0)= -5

this would give you

y = 8-5x

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3 years ago

Is 0.5 greater than or less than 6/10

Vika [28.1K]

6/10 is equal to 0.6 and 0.6 is greater than 0.5

7 0

3 years ago

Read 2 more answers

Find the unknown side length, x. Write your answer in simplest radical form.

Volgvan

Using the Pythagorean Theorem, you should get 45 [9 + 36]. Then, take the square root of 45 and simplify it to 3√5.

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3 years ago

A water tank has a diameter of 15 ft and is 22 ft high. a. What is the volume of the tank in ft?? b. In m?? c. In cm?

rodikova [14]

Answer:

a) $V = 3887.72 ft^{3}$

b) $V = 104.97 m^{3}$

c) $V = 104,968,468.538 cm^{3}$

Step-by-step explanation:

A tank has the format of a cylinder.

The volume of the cylinder is given by:

$V = \pi r^{2}h$

In which r is the radius and h is the heigth.

The problem states that the diameter is measured to be 15.00 ft. The radius is half the diameter. So, for this tank

$r = \frac{15}{2} = 7.50$ ft

The height of the tank is 22 ft, so $h = 22$ .

a) Volume of the tank in $ft^{3}$ :

$V = \pi r^{2}h$

$V = pi*(7.5)^2*22$

$V = 3887.72 ft^{3}$

b) Volume of the tank in $m^{3}$ :

We must convert both the radius and the height to m.

Each feet has 0.30 m, so:

Radius:

1 feet - 0.30m

7.5 feet - r m

$r = 7.5*0.30$

$r = 2.25m$

Height

1 feet - 0.30m

22f - h m

$h = 22*0.30$

$r = 6.60m$

The volume is:

$V = \pi r^{2}h$

$V = pi*(2.25)^2*6.60$

$V = 104.97 m^{3}$

c) Volume of the tank in $cm^{3}$ :

Each m has 100 cm.

So $r = 2.25m = 225cm$

$h = 6.60m = 660cm$

The volume is:

$V = \pi r^{2}h$

$V = pi*(225)^2*660$

$V = 104,968,468.538 cm^{3}$

7 0

4 years ago

1. Solve the rational equation quantity 4 times x plus 3 end quantity divided by 5 equals quantity 8 times x minus 1 end quantit

Vladimir [108]

Answer:

1. x = 8

2. $x=-\dfrac{3}{2}$

Step-by-step explanation:

1. Solve the rational equation

$\dfrac{4x+3}{5}=\dfrac{8x-1}{9}$

First, cross multiply:

$9(4x+3)=5(8x-1)$

Now, use distributive property:

$36x+27=40x-5$

Separate terms with x and without x into different sides of equation:

$36x-40x=-5-27$

Simplify:

$-4x=-32$

Divide by -4:

$x=8$

2. The rational function

$f(x)=\dfrac{x-4}{2x+3}$

This rational function is undefined for all values of x, for which the denominator is equal to 0. Find these values:

$2x+3=0\\ \\2x=-3\\ \\x=-\dfrac{3}{2}$

This means that the line $x=-\dfrac{3}{2}$ is a vertical asymptote for the rational function f(x).

4 0

3 years ago