What is an equation of the line that is parallel to y=9-5x and passes though (0,8)?

Mathematics

1 answer:

Murljashka [212]3 years ago

8 0

y = 8-5x

Step-by-step explanation:

When two lines are parallel, it means their gradients are the same.

from the given equation

y = 9-5x

and comparing with the general equation of a line

y = mx+c, where m is the gradient, and c is the <em>y-intercept, </em>

m = -5

you can form a line parallel to that using the points (0,8)

(y-8)/(x-0)= -5

this would give you

y = 8-5x

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Answer:

A = 18.85ft^2
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Step-by-step explanation: I hope it helps :)

$Surface\: area=\:2\pi rh+2\pi r^2\\h = 2ft\\diameter = 2ft\\Radius = d/2=2/2=1ft\\\\A=( 2\times 3.141\times1\times2)+(2\times 3.141 \times 1^2)\\A = (12.564)+(6.282)\\A = 18.846\\A = 18.85ft^2$

$Area \:of\: square = A=a^2\\A = 3^2\\A=9\\Area\:of \:one \:rectangle\: = (l\times b)\\ A = (8\times 3)\\A = 24cm^2\\\\A = 2(Area\: of\: square)+2(Area\: of \:rectangle)\\A = 2(9)+4(24)\\A = 18+96\\A =114cm^2$

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