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Ede4ka [16]
3 years ago
7

An experiment is being designed to compare relief from dizziness given by a nbspnew nbspdrug comma a nbspcommonly used nbspdrug​

, and a placebo. Each subject who suffers from dizziness and volunteers for the study is observed on three separate​ days, with a different treatment used each day. There are two days between​ treatments, so that a treatment does not have a​ carry-over effect for the next treatment assigned. a. What are the blocks in this block​ design? What is this type of block design​ called? b. What does it mean if the study is conducted as a​ double-blind study? c. How can randomization within the blocks be incorporated into the​ study?
Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer: Find the explanation below.

Step-by-step explanation:

1a. Blocks in this experiment include Age, Gender, genetic differences, Individuals with preexisting health challenges, Response to drugs. Blocking is the separation of subjects into homogeneous groups so as to limit nuisance factors. Nuisance factors affect the response of the subjects of the experiment but are not of foremost importance to the experimenter.

1b. The block design is a randomized block design because the experimenter knows that there is a difference between the groups.

2. If the study is conducted as a double-blind study, it means that both the experimenter and the subjects have no knowledge of the group they fall in. That is, whether they are administered the new drug, a commonly used Drug or a placebo. This will reduce bias, a situation in which the subjects react to treatment because of some preconceived ideas they have on how the treatment will affect them.

3. Randomization involves randomly assigning subjects of an experiment to different homogeneous groups. Introducing randomization might mean first classifying the subjects by gender or age into blocks. Members from each block are now randomly assigned to the treatment groups.

Elis [28]3 years ago
5 0

Answer:

if the experiment is properly randomized and the study reveals a statistical difference between treatments, the study can conclude that the treatment is the cause of difference.

Since, the sample size is unknown to us, we can't generalize it to the population of all hay fever sufferers.

So Statement (i) is correct but Statement (ii) is not. hence, Option(c) is the correct choice. (Ans).

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(-14 + 3/2b) - (1 + 8/2b)<br><br> A.-5/2b - 11<br> B. 4b + 13/2<br> C. -15 - 5/2b<br> D. 8b - 15
Darya [45]
<span>(-14 + 3/2b) - (1 + 8/2b)
= -14 - 1 + 3/2b - 8/2b
= -15 - 5/2b

In short, Your Answer would be Option C

Hope this helps!</span>
7 0
3 years ago
Read 2 more answers
A middle school football player, Bo, is just learning how to kick field goals. Currently, he only makes 1/3 of his kicks. A numb
Zolol [24]

Currently, he only makes 1/3 of his kicks. ... A number cube is being used to simulate the result of Bo's kicks where the numbers 11 or 22

8 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
What does 5/3 x 5 equal?
Bas_tet [7]

Answer:

5/3 x 5/1

multiple straight across

25/3

4 0
4 years ago
Read 2 more answers
PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!
Yuki888 [10]

Answer:

.3 feet

Step-by-step explanation:

3.8 - 3.5 = .3

5 0
3 years ago
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