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Grace [21]
3 years ago
14

3(x-4)=2x-7+x which one A. Infinitesolutions B.x=0 C.x=3 D.x=-2 E.x=-3

Mathematics
1 answer:
BARSIC [14]3 years ago
4 0

Answer:

no solutions

Step-by-step explanation:

I attached the pic of solution

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Write 0.87 as a fraction in simplest form.
TEA [102]
Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1

Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's

Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100

N / D = 87 / 100

Simplifying our fraction

= 87/100

<span>= 87/100</span>
8 0
3 years ago
Find the area of the triangle.<br> PLEASE HELP ASAP!
tatyana61 [14]

Answer:

D 111.4 cm²

Step-by-step explanation:

5 0
2 years ago
What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?
Nimfa-mama [501]

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = \frac{\alpha }{360} X \pi r^2

On substituting the value, we get:

A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2

Therefore, the area of the sector is 86.81π mm²

3 0
3 years ago
Which graph below shows a line that contains ordered pairs that are solutions of the equation shown?
Vinvika [58]

Given:

The equation is:

y=-x+4

To find:

The graph of the line that contains ordered pairs that are solutions of the given equation.

Solution:

We need to find the graph of the given equation.

We have,

y=-x+4

At x=0, we get

y=-0+4

y=4

So, the x-intercept of the given equation is at point (0,4).

At y=0, we get

0=-x+4

x=4

So, the y-intercept of the given equation is at point (4,0).

From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).

Therefore, the correct option is C.

7 0
3 years ago
Does anyone know how to do this
Thepotemich [5.8K]

Answer:

<u>The</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>B</u>

Step-by-step explanation:

x + 5 \geqslant 1 \\ x \geqslant 1 - 5 \\ x \geqslant  - 4

then:

x - 7 <  - 3 \\ x <  - 3 + 7 \\ x < 4

therefore, interval [limits] of x:

- 4 \leqslant x < 4

4 0
3 years ago
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