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3 years ago

Write an expression for the calculation subtract 10 divided into fifths from 20 divided in half

Mathematics

1 answer:

crimeas [40]3 years ago

4 0

20/2-10/5. You divide 20 by 2 and subtract that from 10 divided by 5

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I need help asap....................

docker41 [41]

Based on the given points, the point that is located on the y-axis is (0,7).

<h3>Which point is on the y axis?</h3>

The point that is on the y-axis should have a coordinate such that x is equal to 0.

This leads to the point being on the y-axis because the nonzero coordinate of the y axis would then have to be placed on the same axis.

The only point with a 0 coordinate is (0, 7) so this is the point that is located on the y-axis.

Find out more on points on the y-axis at brainly.com/question/4656315

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7 0

2 years ago

What is the equation for a geometric sequence with a first term of 2 and second term of -8?

Naya [18.7K]

A(1) = 2
r = a(2)/a(1) = -8/2 = -4

$a(n) =a {(r)}^{n - 1} \\ a(n) = 2 {( - 4)}^{n - 1}$
Answer will be D.

!! Hope It Helps !!

4 0

3 years ago

If i have $50 dollars and get $20 dollars a week how much money do i nees to save to get $200 in a month?

ipn [44]

200-50= 150
So you need to get 150 dollars in a month. If you get 20 dollars a week, then 150/20 will give you 7.5. So it will take you 7.5 weeks to get 150 dollars

4 0

3 years ago

Sorry, but I also need help on this

Fudgin [204]

Answer:

I think it's A

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

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Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago