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3 years ago

On a two question true or false quiz what is the probability of guessing both answer answer correctly

Mathematics

1 answer:

algol133 years ago

6 0

25% chance of guessing each question correctly

50% chance to guess one correctly

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6 students share 4 bagels equally

babunello [35]

They would each get one and a half bagels because 6/4= 1.5

3 0

4 years ago

In a particular country, the coins come in the denominations 1, 15 and 50 schillings. Whilst visiting this country, Peter bought

ELEN [110]

Answer:

Step-by-step explanation:

Depending on the tools available to your 11y.o., it's a typical question for linear inequalities.

Where a,b,c are the # of 1,15,50 coins given by the buyer, and d,e,f the # of coins given back by the seller.

1×a + 15×b + 50×c > 1×d + 15×e + 50×f

a+b+c+1>=d+e+f

a+b+c >=2

Now, there are other clues in the text :

If the seller gives back money, then you didn't pay with 1's, otherwise, it means you overpay and you could have given fewer coins. So a=0.

Similarly, the seller cannot give you back a coin of 50, otherwise, you could have given fewer coins as the buyer. So f=0.

So that gives :

15×b + 50×c > 1×d + 15×e

b+c+1>=d+e

b+c >=2

From that point on, there is only a handful of scenarios to test.

5 0

2 years ago

Which linear function has the same y-intercept as the one that is represented by the graph? On a coordinate plane, a line goes t

barxatty [35]

Answer:

The answer is A

Step-by-step explanation:

._.

5 0

3 years ago

Read 2 more answers

Allison flipped a coin twenty times. She flipped heads 4 times and tails 16 times. What is the experimental probability that All

steposvetlana [31]

Answer:

C. 20%

Step-by-step explanation:

4 times out of 20 is 20%

8 0

3 years ago

I need help finding the inverse of this problem

fomenos

$y=\sqrt{x-1}+6$

(Notice that we always have $y\ge6[tex].)Swap [tex]x$ and $y$ , then solve for $y$ :

$x=\sqrt{y-1}+6$

$x-6=\sqrt{y-1}$

$(x-6)^2=(\sqrt{y-1})^2$

$(x-6)^2=y-1$

$y=(x-6)^2+1$ (this is the inverse)

###

This inverse is valid only for $x\ge6$ . Why?

Suppose we take $x=0$ . Then

$y=(0-6)^2+1=37$

This would suggest that in the original equation, we should get $x=37$ when $y=0$ . But when we check this, we end up with

$0=\sqrt{37-1}+6=\sqrt{36}+6=6+6=12$

which is clearly not true.

6 0

3 years ago