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Orlov [11]
3 years ago
13

the probability that a twelve year old has a brother or sister is 25%. suppose you survey 300 twelve year olds. about how many d

o you think will have a brother or sister?
Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

n(B U S) = 75

Step-by-step explanation:

Explanation:-

<u>Probability</u>:-

P(E) = \frac{number of elements events in E}{total number of elementary events in the random experiment}

P(E) = \frac{m}{n}

Let 'B' be the event of having twelve year old brother

Let 'S' be the event of having twelve year old sister

given data  P(BUS) = 0.25

given total survey  n(survey) = 300

we have to find the value is n(BUS) =?

we will use probability definition we get, P( BUS) =\frac{n(BUS)}{n(survey)}

substitute given values, we will get solution

0.25 = \frac{n(BUS)}{300}

after cross multiplication , we get

n(BUS) = 0.25 X 300

n(BUS) = 75

<u></u>

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Find f(x) and g(x) so the function can be expressed as y = f(g(x)).
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Answer for both pleaseeeeeeeeeee
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0 and yes

Step-by-step explanation:

Let a=6m where m is any integer since a is divisible by 6. (a+12)/3=(6m+12)/3=2m+4 which is also an integer. The remainder is 0.

Since n is divisible by 3, n can be written as 3a, where a is any integer and m can be written as 2b, where b is any integer. n*m+12=6ab+12 which is divisible by 2.

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3 years ago
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Find seven ordered pairs to the equation y=8 - x2. <br><br> NEED IT ASAP PLEASE!!!
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-3   |  9-8=1       | (-3, 1)

-2   | 4-8= -4      | (-2, -4)

-1   | 1-8=-7       | (-1, -7)

0.  | 0-8=-8       |  (0, -8)

1   | 1-8=-7       |  (1, -7)

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A person invest $10,000 into a bank the bank pays 4.75% interest compounded semi annually. To the nearest 10th of a year, how lo
Mama L [17]

Answer:

T is 13.9 years to the nearest 10th of a year

Step-by-step explanation:

In this question, we are to calculate the number of years at which someone who invests a particular amount will have a particular amount based on compound interest.

To calculate the number of years, what we do is to use the compound interest formula.

Mathematically,

A = P(1+ r/n) ^nt

Where A is the final amount after compounding all interests which is $19,200 according to the question

P is the initial amount invested which is $10,000 according to the question

r is the rate which is 4.75% according to the question = 4.75/100 = 0.0475

n is the number of times per year in which interest is compounded. This is 2 as interest is compounded semi-annually

t= ?

we plug these values;

19200 = 10,000(1+0.0475/2)^2t

divide through by 10,000

1.92 = (1+0.02375)^2t

1.92 = (1.02375)^2t

We find the log of both sides

log 1.92 = log [(1.02375)^2t)

log 1.92 = 2tlog 1.02375

2t = log 1.92/log 1.02375

2t = 27.79

t = 27.79/2

t = 13.89 years

The question asks to give answer to the nearest tenth of a year and thus t = 13.9 years

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