Factor this completely

Mathematics

1 answer:

Katena32 [7]3 years ago

8 0

To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, that satisfy two conditions:

ac=jk and b=j+k in this case:

ac=jk=-18 and b=j+k=7 so j and k must be 9 and -2

Now replace bx with jx and kx in the original equation...

x^2-2x+9x-18 and factor the 1st and 2nd pair of terms...

x(x-2)+9(x-2) which is equal to

(x+9)(x-2)

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