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Andreas93 [3]
3 years ago
15

(10−523)⋅(−2)+x=823 Anybody???

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

       x =  - 203

Step-by-step explanation:

(10−523)⋅(−2)+x=823  

( - 513) * (-2) + x = 823

   1026 + x = 823

               x = 823 - 1026

              x =  - 203

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347 students said that they played sports. 58% said that they played basketball. How many students play basketball?
aliya0001 [1]

Answer:

201 students play basketball.

Step-by-step explanation:

total students who played sports = 347

58 % played basketball.

That is ,

   \frac{58}{100} \times 347 = 201.26

Since number of students cannot be in decimals we take the nearest whole number = 201.

6 0
3 years ago
Find the value of x. Round to<br> the nearest tenth.
denpristay [2]

Answer:

\displaystyle x \approx 38.2 ^{\circ}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Pre-Calculus</u>

Law of Sines: \displaystyle \frac{sin(A)}{a} =\frac{sin(B)}{b} =\frac{sin(C)}{c}

  • A, B, C are angle measures
  • a, b, c are leg lengths

Step-by-step explanation:

<u>Step 1: Identify</u>

A = 27°, a = 11

B = x°, b = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [LOS]:                     \displaystyle \frac{sin(27^{\circ})}{11} =\frac{sin(x^{\circ})}{15}
  2. Cross-multiply:                        \displaystyle 11sin(x^{\circ}) = 15sin(27^{\circ})
  3. Isolate <em>x</em> term:                         \displaystyle sin(x^{\circ}) = \frac{15sin(27^{\circ})}{11}
  4. Isolate <em>x</em>:                                  \displaystyle x = sin^{-1}(\frac{15sin(27)}{11})
  5. Evaluate:                                 \displaystyle x = 38.2488 ^{\circ}
  6. Round:                                    \displaystyle x \approx 38.2 ^{\circ}
7 0
3 years ago
In one day, Mr Hanson spent $100
Vladimir79 [104]

Se redujeron $500 de la tarjeta de debito.

7 0
3 years ago
Mr. Rich had 2 times more cars than motorcycles in his garage. After he bought 1 more car and sold 2 motorcycles, there were 3 t
Degger [83]

Answer:

After the sale there were 15 cars and 5 motorcycles

Step-by-step explanation:

c=cars originally

m=motorcycles originally

c=2m  (2 times the cars than motorcycles)

(c+1)  bought 1 car  after sale

sold 1 motor cycle (m-2)  after sale

(c+1) = 3(m-2)   (3 times more cars than motorcycles)


(c+1) = 3(m-2)

distribute

c+1 = 3m-6

substitute c =2m

2m +1 = 3m-6

subtract 2m from each side

2m+1-2m = 3m-6-2m

1 = m-6

add 6 to each side

1+6 = m-6+6

m=7

c = 2m

c = 2(7) =14

c=14

Originally there were 7 motorcycles and 14 cars

After the sale c+1 = 15, m-2 = 5

there were 15 cars and 5 motorcycles

7 0
3 years ago
Read 2 more answers
What’s the value for Y
FinnZ [79.3K]

Answer:28

Step-by-step explanation:

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4 years ago
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