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3 years ago

The volume of a cube is 512 cm3.

Mathematics

2 answers:

Elena-2011 [213]3 years ago

7 0

Answer:

D. The number of cubic units would decrease

Step-by-step explanation:

We are given that,

Volume of a cube = 512 cm³

Since, 1 meter = 100 centimeter

i.e 100 centimeter = 1 meter

Then, 512 centimeter = $\frac{1}{100}\times 512$ = 5.12 m³

Thus, we have that,

The volume of the cube measured in cubic meters is 5.12 m³.

Thus, we get that,

<em>There is no change in the volume of the prism but the number of the cubic units decreases by a factor of 100.</em>

Hence, option D is correct.

ryzh [129]3 years ago

6 0

Well,

$512 cm^{3}\ converted\ to\ m^{3} = 5.12m^{3}$

The actual volume of the cube does not increase, but the number of cubic units decreases. In fact, the number of cubic units decreases by a factor of 100, as the centimeter-to-meter relationship is 100-to-1.

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Y=-x+2 <br> y=-5x-6 <br> What is y and x

tatyana61 [14]

To solve this system of equations, since y is already isolated in both equations, you can set the expressions to equal each other to solve for x:

-x + 2 = - 5x - 6
-x + 5x = -6 - 2
4x = -8
x = -2

Now that we have x, we can substitute it into one of the equations to find y:

y = -(-2) + 2
y = 2 + 2
y = 4

The last step is to substitute both values into both equations to see if they are correct:

4 = -(-2) + 2 --> 4 = 2 + 2 <--True
4 = -5(-2) - 6 --> 4 = 10 - 6 <--True

Answer:
x = -2
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3 years ago

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

777dan777 [17]

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

$Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)$

$Midpoint=\left(-4,1\right)$

Slope of lines NY is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-3-5}{3-(-11)}$

$m=\dfrac{-8}{14}$

$m=\dfrac{-4}{7}$

Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

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3 years ago

furniture maker used 1/2 of a can of paint to paint some chairs. She used 1/6 of a can of paint for each chair. How many chairs

dezoksy [38]

Answer:

3 chairs

Step-by-step explanation:

1/2 is the same as 3/6

There are three 1/6 in 3/6.

(3/6) ÷ (1/6) = 3

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3 years ago

What is the measure of the angle at the tail end of the kite? if the top area is where its pointed is 122?

nataly862011 [7]

Answer:

The angle is 58 degrees

Step-by-step explanation:

Given

See attachment for kite

Required

The angle at the tail end

Represent this angle with x.

From the attached kite, we have:

1 angle = 122

2 angles = right-angled

So, we have:

$x + 122 +90+90 = 360$ --- sum of angles in a kite

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Solve for x

$x =- 302 + 360$

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2 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

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3 years ago