In each table, x increases by 1. We start with x = 0 and stop with x = 3. So we will focus on the y columns of each table as those are different.
Let's move from left to right along the four tables.
For the first table, we go from y = 1 to y = 2. That's an increase of 1
Sticking with the first table, we go from y = 2 to y = 4. The increase is now 2
Since the increase is not the same, this means the table is not linear. The y increase must be constant. We can rule out choice A
Choice B can be ruled out as well. Why? Because...
the jump from y = 0 to y = 1 is +1
the jump from y = 1 to y = 3 is +2
The same problem comes up as it did with choice A
Choice C has the same problem, but the increase turns into a decrease half the time. We go from y = 0 to y = 1, then we go back to y = 0 so the "increase" is really a decrease. We can think of it as a negative increase. Regardless, this allows us to rule out choice C
Only choice D is the answer. Each time x goes up by 1, y goes up by 2. Therefore the slope is 2/1 = 2
Answer:
Each angle = 31 degree
Step-by-step explanation:
3x+10 = 5x-4
14=2x
7=x x=7
21+10=31
35-4=31
Here's the link to the answer! Couldn't attach it here!
Answer:
7) BC = 10
8) BD = 20
Step-by-step explanation:
7) The segment addition theorem tells you ...
AB +BC +CD = AD
(3x+2) +(2x+4) +(3x-2) = 28
8x +4 = 28 . . . . collect terms
8x = 24 . . . . . . . subtract 4
x = 3 . . . . . . . . . divide by 8
BC = 2x+4 = 2(3) +4
BC = 10
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8) AB +BD = AC +CD
(2x -14) +(-7 +3x) = (2x -3) +(9)
5x -21 = 2x +6
3x = 27
x = 9
BD = -7 +3x = -7 +3(9)
BD = 20
