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1 year ago

Evaluate (35 = x)

Mathematics

2 answers:

ratelena [41]1 year ago

7 0

Answer:

the answer : a

equation : 35 = x

35 = 7

35/7 = 5

5-2 = 3

Reika [66]1 year ago

5 0

Hey there!

(35 ÷ x) - 2

= (35 ÷ 7) - 2

= (5) - 2

= 5 - 2

= 3

Therefore, your answer is: Option A. 3

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Mezclas de alimentos. Un chef repostero creó una solución de azúcar de 50 onzas constituida por 34% de azúcar con una solución d

Kay [80]

Answer:

Las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

Step-by-step explanation:

Podemos estimar la proporción de ingredientes mediante el siguiente promedio ponderado:

$0.34= \frac{0.2\cdot m_{A} + 0.4\cdot m_{B}}{m_{A}+m_{B}}$ (1)

Donde:

$m_{A}$ - Masa de la solución al 20 %, en onzas.

$m_{B}$ - Masa de la solución al 40 %, en onzas.

Podemos simplificar la formula como sigue:

$0.2\cdot x + 0.4\cdot (1-x) = 0.34$ (2)

Donde $x$ es la proporción de la solución al 20 % dentro de la solución final, sin unidades.

Ahora resolvemos para $x$ en (2):

$0.4-0.2\cdot x = 0.34$

$0.2\cdot x = 0.06$

$x = \frac{0.06}{0.2}$

$x = 0.3$

Este resultado quiere decir que la solución al 34 % es el resultado de 30 % de la solución al 20 % y 70 % de la solución al 40 %. Si conocemos que la solución final tiene una masa de 50 onzas, entonces las cantidades empleadas para su preparación son: 15 onzas de solución al 20 % y 35 onzas de solución al 40 %.

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2 years ago

What is the value of x drawing not to scale

AVprozaik [17]

angle x would end up being equal to 71 degrees.

8 0

2 years ago

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f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$

Step 3: Evaluate the function at the left endpoints

$f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3$

$f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386$

$f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964$

$f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527$

$f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0$

$f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527$

Step 4: Apply the Left Riemann Sum formula

$\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315$

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

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2 years ago

HELP PLEASE!! Please don't give me sites or links, those won't work since the site is blocked!

rewona [7]

Answer:

x = -68

Step-by-step explanation:

1) multiply the two members by 17

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2 years ago

The sum of two integers is 74. The larger is 26 more than twice the smaller.Find the two integers

irina [24]

Let... the smaller integer be x

Then, the larger integer is 2x+26(Two times.. =2x, 26 more... is =2x+26

Both added is 74

2x+26=74

2x=74−26

2x=48

x=24

5 0

2 years ago

Read 2 more answers