From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
You need to divide 6 by 4/5.
6÷4/5
6 x 5/4
30/4
7 2/4 = 7 1/2 answer
Answer:
10.5 in
Step-by-step explanation:
Given

Required
Find length AC
The question is not detailed enough; so, I'll assume that b represents line AC.
Having said that;
We start by multiplying both sides by b



Divide both sides by tan(55)


Find tan(55)


<em>(Approximated)</em>
<em />
Length AC is 10.5
<em>Refer to the attachments!!</em><em>~</em>
Answer:
Answer is 225.
We have to find the sum of 15 terms of the series
sigma 1 to 15 (2n-1)
This can be split as per summation terms as
sigma 2n - sigma 1
sigma 2n can again be simplified by taking 2 outside
sigma 2n= 2 times sum of natural numbers of 1 to 15
= 2(15)(16)/2= 240
sigma 1= 1+1+...15 times= 15
Hence final answer is
= 2 times sigma n - (n) = 240-15 = 225.
Step-by-step explanation: