3 years ago

EASY QUESTION PLEASE HELP

Mathematics

2 answers:

Serga [27]3 years ago

7 0

Answer:

The answer is the first table, or Table 1.

Step-by-step explanation:

Happy to help! c:

mr_godi [17]3 years ago

3 0

Answer:

Yea its table 1

Step-by-step explanation:

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If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .

Lelechka [254]

$\sin^2\theta+\cos^2\theta=1\implies \cos\theta=\pm\sqrt{1-\sin^2\theta}$

Since $\sin\theta=-\dfrac8{17}$ , it follows that

$\cos\theta=\pm\sqrt{1-\dfrac{64}{289}}=\pm\sqrt{\dfrac{225}{289}}=\pm\dfrac{15}{17}$

where the sign depends on the location of the terminal side of the angle. Since the terminal side lies in the fourth quadrant, that means the cosine of the angle is positive, so

$\cos\theta=\dfrac{15}{17}$