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3 years ago

Draw a pair of vertical angles with a given measure

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

Vertical Angles are the congruent angles opposite each other when two lines cross

see the attached figure to better understand the problem

m<ACD=m<BCE ------> by vertical angles

m<ACB=m<DCE ----> by vertical angles

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Consider functions f and g in the table below.

nikitadnepr [17]

The answer is A.) x = 2

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3 years ago

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to crea

nignag [31]

The expression that would be added to both sides is (b/2a)^2

<h3>How to determine the expression?</h3>

The equation is given as:

x^2 + b/ax + __ = c/a + __

Take the coefficient of x

b/a

Divide by 2

b/2a

Square the expression

(b/2a)^2

Hence, the expression that would be added to both sides is (b/2a)^2

Read more about quadratic equation at:

brainly.com/question/10449635

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1 year ago

The object of the game is to toss a beanbag in the circular hole of a 48-by-24-inch board. If the diameter of the circle is 6 in

larisa [96]

Answer:

Geometric probability of an object hitting a circular hole is 0.0245.

Step-by-step explanation:

We have given,

A board of size 48 by 24 inch. There is a circular hole in the board having diameter 6 inches.

So,

Area of a board = 48 × 24 = 1152 square inches

And area of circular hole = π×r² {where r = diameter/2 = 6 / 2 = 3 inches}

Area of circular hole = π×3² = 9π = 28.27 square inches

Now, we need to find the geometric probability of an object will hit the circle.

Geometric probability = Area of circular hole / Area of board

Geometric probability = $\frac{28.27}{1152}$

Geometric probability = 0.0245

hence geometric probability of an object hitting a circular hole is 0.0245.

6 0

3 years ago

Guys help me please

elena-14-01-66 [18.8K]

There are several ways that can help someone recover after they are injured. After the injury occurs, it is best to go to the doctor or hospital to get the injury, if need be, checked on or fixed. Another thing that can help is if the person rests and does not do any heavy-lifting or do to many activities that can strain the injury. After an injury occurs, if you do not rest there is more of a likelihood that you can damage it more and also rest helps the body heal. There are also several medicine's that are meant to help relieve pain after an injury occurs.

Hope it helps.

4 0

3 years ago

(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

$c = \dfrac{3}{8} \ g/L$

4 0

3 years ago