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patriot [66]
3 years ago
10

Evaluate the expression: Arctan(-sqrt3)

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0
It means find the angle whose tangent equals - sqrt (3)
the negative square root of 3  = (-<span> <span> <span> 1.7320508076) </span>
Looking up the arc tan  </span></span><span>(-1.7320508076</span> ) on this page:
http://www.1728.org/trigcalc.htm
we find it equals -60 degrees
 


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3. Evaluate at the given value: g(x)=-2x+7, g^-1(-2)​
Juli2301 [7.4K]

Answer:

<h2>{g}^{ - 1} ( - 2)  =  \frac{9}{2}</h2>

Step-by-step explanation:

To find g-¹( 2) we must first find g-¹(x)

To find g-¹(x) equate g(x) to y

That's

y = g(x)

We have

y = - 2x + 7

Now interchange the terms that's x becomes y and y becomes x

We have

x = - 2y + 7

Make y the subject in order to find g-¹(x)

Move 7 to the left side of the equation

- 2y = x - 7

Multiply both sides by - 1

We have

2y = 7 - x

Divide both sides by 2 to make y stand alone

That's

<h3>y =  \frac{7 - x}{2}</h3>

So we have

<h3>g ^{ - 1} (x) =  \frac{7 - x}{2}</h3>

Now to find g-¹(- 2) substitute the value of x that's - 2 into the expression

We have

<h3>{g}^{ - 1} ( - 2) =  \frac{7 -  - 2}{2}  \\ {g}^{ - 1} ( - 2)  =  \frac{7 + 2}{2}</h3>

We have the final answer as

<h3>{g}^{ - 1} ( - 2)  =  \frac{9}{2}</h3>

Hope this helps you

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