Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer: The area is 5024 yrd^2
Step-by-step explanation:
80 is the diameter to we need to divide it by 2 to find the radius
80/2= 40
A= 3.14* 40^2
A = 3.14 * 1600
A= 5024
Answer:
y =
- 1
Step-by-step explanation:
y - y1 = m (x - x1)
y + 5 =
(x + 12)
y + 5 =
x + 
y + 5 =
x + 4
y =
x - 1
Hope this was helpful :)
Answer:
-184
Step-by-step explanation:
The 0.4 isn't 5 or greater so it won't be rounded up as 1.
3.
30 divided by 10 equals 3