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Daniel [21]
3 years ago
14

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a gold chip, not replacing it

, and then randomly choosing another gold chip?
Mathematics
1 answer:
nadezda [96]3 years ago
8 0
The probability would be 1/15. 
The first draw, taking a gold coin is 3/10. 
Since we don't replace it, we draw again, but a value less- 2/9. 
We multiply that together and get 6/90, then simplify it :)<span />
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Help<br> Find the volume of this cone.<br> Use 3 for TT.
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Answer:

180ft^{3}

Step-by-step explanation:

Volume of a cone:

V=\pi r^{2} \frac{h}{3}

Take \pi as 3, as mentioned in the question

'r' is 'radius' ⇒ {diameter is given so divide by 2: 12/2 = 6}

'h' is 'height'

V=(3)(6)^{2} (\frac{5}{3} )

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A basketball player made 66 out of 75 free throws. What percent is this?
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Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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