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Daniel [21]
3 years ago
14

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a gold chip, not replacing it

, and then randomly choosing another gold chip?
Mathematics
1 answer:
nadezda [96]3 years ago
8 0
The probability would be 1/15. 
The first draw, taking a gold coin is 3/10. 
Since we don't replace it, we draw again, but a value less- 2/9. 
We multiply that together and get 6/90, then simplify it :)<span />
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(ASAP LOTS OF POINTS)
shusha [124]

Answer:

52 inches by 29 inches

Step-by-step explanation:

Let one side by 16x   and the other side be 9x

We know the diameter is 60 inches

Using the Pythagorean theorem

a^2 + b^2 = c^2

(16x) ^2 + ( 9x) ^2 = 60 ^2

256 x^2 + 81x^2 = 3600

Combine like terms

337 x^2 = 3600

Divide each side by 337

337x^2 /337 = 3600/337

x^2 =10.68249258

Take the square root of each side

sqrt(x^2) =sqrt(10.68249258)

x =3.268408264

The sides are 16x by 9x

16*(3.268408264) =52.29453223  or 52

9 *(3.268408264)= 29.41567438 or 29

5 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt
Goryan [66]

Answer:

A) The value of a is <u>29</u>.

B) The value of b is <u>greater than 29</u>.

C) In both part A and part B we have used a common property  which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

a-9=20

We have to solve for a.

a-9=20

By using addition property of equality, we will add both side by 9;

a-9+9=20+9\\a=29

Hence the value of a is <u>29</u>.

Solving for Part B.

Given,

b-9>20

We have to solve for b.

b-9>20

By using addition property of inequality, we will add both side by 9;

b-9+9>20+9\\b>29

Hence the value of b is <u>greater than 29</u>.

Solving for Part C.

In both part A and part B we have used a common property  which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

5 0
3 years ago
What is the approximate solution to the equation 3t=29 ? 0.3263 3.0650 3.3672 9.6667
Norma-Jean [14]

Answer:

9.6667

Step-by-step explanation:

3t=29

Divide each side by 3

3t/3 = 29/3

t = 29/3

Three goes into 29  nine times  (3*9 = 27 ) with 2 left over

t =  9 2/3

We know 1/3 = .3 repeating

so 2/3  = .6 repeating


t = 9 .6 repeating

7 0
2 years ago
Read 2 more answers
Nick starts with 20 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number of
zlopas [31]

Answer:

Eric's expression is :

20(\frac{1}{4})^w

and Andrea's is :

(1-0.5)^w

In Eric's expression, 20 represents the initial amount of substance with which he has started the experiment. \thinspace \frac{1}{4}\thinspace is the amount of substance left after each time period (in this case, each week).The variable w in this case represents the number of weeks.

Andrea's expression can be written as :

1\cdot (1-0.5)^w

The one outside of parentheses represents the initial amount of the substance. The one inside of parentheses represents 100% of the original amount of the substance. 0.5 represents the 50% of the substance that is lost each time period. The variable w in this case represents the number of weeks.

8 0
3 years ago
Read 2 more answers
Mary Stevens earns 6 an hour at jod and is entitled to time and a half for overtime and double time on holidays. Last week she w
Dennis_Churaev [7]
40 x $6=$240 
<span>6.5 x $9=$58.50 </span>
<span>8 x $ 12=$ 96 </span>

<span>Answer $394.50</span>
4 0
3 years ago
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